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steposvetlana [31]
3 years ago
8

Are the waves in this application transverse, longitudinal, or both? If either transverse or longitudinal waves are missing from

the application explain why?On what parameters of the media (pressure, temperature, mass, density,... ) does the wave speed depend?
Physics
1 answer:
lianna [129]3 years ago
4 0

Answer:

Explanation:

consider the radio wave which is electro magnetic wave used for radio communication.

  1. the wave propagates for air or vacuum.
  2. the wave presented by air is a transverse wave
  3. the radio wave speed is constant that is, equals to the speed of light as it is now electromagnetic waves.
  4. now the general relationship between frequency, speed and wavelength is given by

                         c = v/lander

               lander = c/v          

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PLEASE HELP! I NEED TO ANSWER THIS QUICKLY!
rodikova [14]

Answer:

I'm not a genius ok?

Explanation:

1. Radar communication, Analysis of the molecular and atomic structure, telephone communication

2. c

4 0
3 years ago
When the distance between two stars decreases by one-third, the force between them
pashok25 [27]

Answer:

the force will increase by a factor 2.25

Explanation:

The gravitational force between the two stars is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two stars

r is the distance between the stars

If the distance is decreased by one-third, it means that the new distance is 2/3 of the previous distance

r'=\frac{2}{3}r

So the new force will be

F'=G\frac{m_1 m_2}{(\frac{2}{3}r)^2}=\frac{9}{4} G\frac{m_1 m_2}{r^2}=2.25 F

So, the force will be 2.25 times the previous value.

4 0
3 years ago
If a nearsighted person has a far point df that is 3.50 m from the eye, what is the focal length f1 of the contact lenses that t
Anastaziya [24]

Answer:

f1 = -3.50 m

Explanation:

For a nearsighted person an object at infinity must be made to  appear  to be at his far point which is 3.50 m away. The image of an object at infinity must be formed on the same side of the lens as the object.

∴ v = -3.5 m

Using mirror formula,

i/f1 = 1/v + 1/u

Where f1 = focal length of the contact lens, v = image distance = -3.5 m, u =         object distance = at infinity(∞) = 1/0

∴ 1/f1 = (1/-3.5) + 1/infinity

  Note that, 1/infinity = 1/(1/0) = 0/1 =0.

∴ 1/f1 = 1/(-3.5) + 0

  1/f1 = 1/(-3.5)

Solving the equation by finding the inverse of both side of the equation.

∴ f1 = -3.50 m

 Therefore a converging lens of focal length  f1 = -3.50 m

would be needed by the person to see an object at infinity clearly

8 0
3 years ago
What parts to all cells have in common?
natima [27]
<span>1. Plasma membrane - also known as cell membrane. It is 'the skin of a cell', which acts as a physically controlling barrier for the entrance and exit of materials. It's made up of proteins and lipids.
2. Cytoplasm - everything inside the cell (but not including the nucleus). Much of the cytoplasm is a transparent and gel-like material known as cytosol; cell structures are suspended in it.
3. Ribosomes - these are organelles that are in charge of making proteins.
<span>4. DNA - Molecules containing the genetic code of a cell, which tells the cell what to do. It is located in the nucleus for eukaryotic cells; for prokaryotic cells, it is located in a part of the cell called the nucleoid.</span></span>
7 0
3 years ago
What is a gravitational field and how its strength be measured
Yakvenalex [24]
A gravitational field is the field generated by a massive body, that extends into the entire space. Every object with mass m experiences a force F when immersed in a gravitational field. The intensity of the force is equal to
F= \frac{GM}{r^2}  m
where G=6.67 \cdot 10^{-11} m^3 Kg^{-1} s^{-2} is the gravitational  constant, M is the mass of the source of the field (e.g. the mass of a planet), and r is the distance between the object and the source of the field. The force is always attractive. 

A possible way to measure the intensity of a gravitational field is by measuring the acceleration a of the object immersed in this field. In fact, for Newton's second law we have:
F=ma
but since 
F= \frac{GM}{r^2} m
we can write
a =  \frac{GM}{r^2}
Therefore, by measuring the acceleration of the object, we also measure the intensity of the field.

5 0
3 years ago
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