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Nata [24]
3 years ago
9

A dialogue between two friends discussing about teej​

Physics
1 answer:
liq [111]3 years ago
5 0

"Holy cow !  Can you believe it, Lakshmi ? !  Here it is almost Shraavana again.  Soon the rains will be blowing and the Teej will be biting.  Let's sing, dance, and pray together while it's still so nice outside."

"OK, Priya.  Great idea.  Count me in.  Let's go."

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Please help!!! zoom in to read it clearly
Artist 52 [7]

Answer:

imma try nd help cuz i havent seen anybody answer so

1.sara

2.same for both

3.tom

Explanation:

4 0
3 years ago
A parallel-plate vacuum capacitor has 8.38 J of energy stored in it. The separation between the plates is 2.30 mm. If the separa
Elanso [62]

Answer:

Explanation:

plate separation = 2.3 x 10⁻³ m

capacity C₁ = ε A / d

= ε A / 2.3 x 10⁻³

C₂ = ε A / 1.15 x 10⁻³

\frac{C_2}{C_1} = \frac{2.3}{1.15}

a ) when charge remains constant

energy = \frac{q^2}{2C}

q is charge and C is capacity

energy stored initially E₁= \frac{q^2}{2C_1}

energy stored finally E₂ = \frac{q^2}{2C_2}

\frac{E_1}{E_2} = \frac{C_2}{C_1} = \frac{2.3}{1.15}

E_2 = \frac{1.15}{2.3 } \times E_1

= \frac{1.15}{2.3 } \times 8.38

= 4.19 J

b )

In this case potential diff remains constant

energy of capacitor = 1/2 C V²

energy is proportional to capacity as V is constant .

\frac{E_2}{E_1} = \frac{C_2}{C_1}

\frac{E_2}{8.38} = \frac{2.3}{1.15}

E_2 = 16.76 .

8 0
3 years ago
The fastest measured pitched baseball left the pitcher's hand at a speed of 42.0 m/s. If the pitcher was in contact with the bal
I am Lyosha [343]

Answer:

The acceleration and time are 588 m/s² and 0.071 sec respectively.

Explanation:

Given that,

Speed = 42.0 m/s

Distance = 1.50 m

(a). We need to calculate the acceleration

Using equation of motion

v^2=u^2+2as

a=\dfrac{v^2-u^2}{2s}

Put the value in the equation

a=\dfrac{42.0^2-0}{2\times1.50}

a=588\ m/s^2

(b). We need to calculate the time

Using equation of motion

v = u+at

t=\dfrac{v-u}{a}

t=\dfrac{42.0-0}{588}

t=0.071\ sec

Hence, The acceleration and time are 588 m/s² and 0.071 sec respectively.

8 0
3 years ago
A magnetic field would be produced by a beam of
kumpel [21]
3 protons should be your answer
4 0
3 years ago
If the index of refraction of a medium is 1.4, determine the speed of light in that medium.
Damm [24]

The speed of light in that medium is 2.14 \times 10^8 \ m/s.

<u>Explanation:</u>

It is known that the light's speed is constant when it travels in vacuum and the value is 3 \times 108 m/s. When the light enters another medium other than vacuum, its speed get decreased as the light gets refracted by an angle.

The amount of refraction can be determined by the index of refraction or refractive index of the medium. The refraction index is measured as the ratios of speed of light in vacuum to that in the medium. It is represented as  η = \frac {c}{v}

So, here η is the index of refraction of a medium which is given as 1.4, c is the light's speed in vacuum (3 \times 10^8 ms^-^1) and v is the light's speed in that medium which we need to find.

1.4=  \frac{(3 \times 10 ^ 8)} {v}

v=  \frac {(3 \times 10^8)}{1.4} =2.14 \times 10^8 \ m/s

Thus the speed of light in that medium is 2.14 \times 10^8 \ m/s.

3 0
3 years ago
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