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tia_tia [17]
3 years ago
7

Which statement is true according to Newton's second law of motion? A. An object accelerates in the direction opposite to the di

rection of the force applied. B. An object accelerates in the direction perpendicular to the direction of the force applied. C. An object accelerates in the same direction as that of the force applied. D. An object undergoes no acceleration on the application of force. E. An object’s acceleration is independent to the force applied.
Physics
2 answers:
antiseptic1488 [7]3 years ago
7 0

According to Newton's second law of motion, C. an object accelerates in the same direction as that of the force applied.

You don't see this when you see the 2nd law's formula written as Force=mass·Acceleration ... there doesn't seem to be any information about directions there.

The thing is that this is supposed to be a VECTOR equation, like <em>Force</em>=m·<em>Acceleration .</em>  Written like that, it says that <em>Force</em> and <em>Acceleration</em> are vectors, and both sides of the vector equation have the same direction, so the vectors <em>Force</em> and <em>Acceleration</em> both have the same direction.

Tom [10]3 years ago
4 0

Answer:

C. An object accelerates in the same direction as that of the force applied.

Explanation:

 An object accelerates in the same direction as that of the force applied.

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A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.) mm/s

Answer:

The drift velocity is v  = 0.0002808 \ m/s

Explanation:

From the question we are told that

    The current on the copper is  I  = 20 \ A

     The cross-sectional area is  A =  5.261 \ mm^2 =  5.261 *10^{-6} \ m^2

The number of copper atom in the wire is  mathematically evaluated

      n  =  \frac{\rho *  N_a}Z}

Where \rho is the density of copper with a value \rho =  8.93 \ g/m^3

          N_a is the Avogadro's number with a value N_a  = 6.02 *10^{23}\ atom/mol

         Z  is the molar mass of copper with a value  Z =  63.55 \ g/mol

So

     n  =  \frac{8.93 * 6.02 *10^{23}}{63.55}

     n  = 8.46 * 10^{28}  \  atoms /m^3

Given the 1 atom is equivalent to 1 free electron then the number of free electron is  

         N  = 8.46 * 10^{28}  \  electrons

The current through the wire is mathematically represented as

         I  =  N * e * v * A

substituting values

        20 =  8.46 *10^{28} * (1.60*10^{-19}) * v *  5.261 *10^{-6}

=>     v  = 0.0002808 \ m/s

       

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