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tia_tia [17]
3 years ago
7

Which statement is true according to Newton's second law of motion? A. An object accelerates in the direction opposite to the di

rection of the force applied. B. An object accelerates in the direction perpendicular to the direction of the force applied. C. An object accelerates in the same direction as that of the force applied. D. An object undergoes no acceleration on the application of force. E. An object’s acceleration is independent to the force applied.
Physics
2 answers:
antiseptic1488 [7]3 years ago
7 0

According to Newton's second law of motion, C. an object accelerates in the same direction as that of the force applied.

You don't see this when you see the 2nd law's formula written as Force=mass·Acceleration ... there doesn't seem to be any information about directions there.

The thing is that this is supposed to be a VECTOR equation, like <em>Force</em>=m·<em>Acceleration .</em>  Written like that, it says that <em>Force</em> and <em>Acceleration</em> are vectors, and both sides of the vector equation have the same direction, so the vectors <em>Force</em> and <em>Acceleration</em> both have the same direction.

Tom [10]3 years ago
4 0

Answer:

C. An object accelerates in the same direction as that of the force applied.

Explanation:

 An object accelerates in the same direction as that of the force applied.

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The relationship between velocities and time is described by this equation: v_f=v_0+a*t, where v_f is the final velocity, v_0 is the initial velocity, a the acceleration, and t is the time during such acceleration is applied.

Solving the equation for the time, and applying to the case: t=\frac{v_f-v_0}{a}=\frac{0\frac{m}{s}-282\frac{m}{s}  }{-201\frac{m}{s^2} }=1.40s, where v_f=0\frac{m}{s} because the sled is totally stopped, v_0=282\frac{m}{s} is the velocity of the sled before braking and, a=-201\frac{m}{s^2} is negative because the deceleration applied by the brakes.

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Then for this case the relationship becomes: x_f-x_0=282\frac{m}{s} *1.40s+\frac{1}{2}(-201\frac{m}{s})*(1.40s)^2=94.22m.

<u>Note that the acceleration is negative because is a braking process.</u>

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