<u>Given information:</u>
Mass of NaCl (m) = 87.75 g
Volume of solution (V) = 500 ml = 0.5 L
Molar mass of NaCl (M) = 58.44 g/mol
<u>To determine:</u>
The molarity of NaCl solution
<u>Explanation:</u>
Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)
i.e. M = moles of solute/liters of solution = n/V
Moles of solute (n) = mass of solute (m)/molar mass (M)
moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles
Therefore,
Molarity of NaCl = 1.499 moles/0.5 L = 2.998 moles/lit ≅ 3 M
<u>Ans: (D)</u>
I believe it is D. They can contain different types of atom the can contain different type of arms and molecule
I can't see the picture, but in general, I believe it is in dropping from the first energy level above the ground state, to the ground state.
Answer:
212.996 or 213 approx.
hope it helps.
Molar mass of Al - 27
Molar mass of N - 14
Molar mass of O - 16
so, the molar mass of (No3)3 will be (14+16×3)3 which is equals to 186.
so, Molar mass of Al(No3)3 will be 186+27 = 213.
