I believe.. The answer you are looking for is A
Answer:
Option a, centimeter
Explanation:
Foot, Inch and Yard are units used in America, UK, and other english-speaking countries.
These countries are currently reviewing the possibility of adapting the measures to the SI. The centimeter is a unit derived from the meter, base unit for measuring length in the SI, and corresponds to the cgs system, where in addition to the centimeter, is constituted by gram and second units
Kate may have payed for 20 strawberries I'm not sure if that is right?? hope I helped
Answer:
![\large \boxed{\textbf{32.7 g}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctextbf%7B32.7%20g%7D%7D)
Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
MM: 102.89 159.81
2NaBr + F₂ ⟶ 2NaF + Br₂
m/g: 25.4
(a) Moles of Br₂
![\text{Moles of Br$_{2}$} = \text{25.4 g Br$_{2}$}\times \dfrac{\text{1 mol Br$_{2}$}}{\text{159.81 g Br$_{2}$}}= \text{0.1589 mol Br$_{2}$}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20Br%24_%7B2%7D%24%7D%20%3D%20%5Ctext%7B25.4%20g%20Br%24_%7B2%7D%24%7D%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20Br%24_%7B2%7D%24%7D%7D%7B%5Ctext%7B159.81%20g%20Br%24_%7B2%7D%24%7D%7D%3D%20%5Ctext%7B0.1589%20mol%20Br%24_%7B2%7D%24%7D)
(b) Moles of NaBr
![\text{Moles of NaBr} = \text{0.1589 mol Br$_{2}$} \times \dfrac{\text{2 mol NaBr }}{\text{1 mol Br$_{2}$}} = \text{0.3179 mol NaBr}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20NaBr%7D%20%3D%20%5Ctext%7B0.1589%20mol%20Br%24_%7B2%7D%24%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B2%20mol%20NaBr%20%7D%7D%7B%5Ctext%7B1%20mol%20Br%24_%7B2%7D%24%7D%7D%20%3D%20%5Ctext%7B0.3179%20mol%20NaBr%7D)
(c) Mass of NaBr
![\text{Mass of NaBr} =\text{0.3179 mol NaBr} \times \dfrac{\text{102.89 g NaBr}}{\text{1 mol NaBr }} = \textbf{32.7g NaBr}\\\\\text{The reaction produces $\large \boxed{\textbf{32.7 g}}$ of NaBr}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20NaBr%7D%20%3D%5Ctext%7B0.3179%20mol%20NaBr%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B102.89%20g%20NaBr%7D%7D%7B%5Ctext%7B1%20mol%20NaBr%20%7D%7D%20%3D%20%5Ctextbf%7B32.7g%20NaBr%7D%5C%5C%5C%5C%5Ctext%7BThe%20reaction%20produces%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B32.7%20g%7D%7D%24%20of%20NaBr%7D)
The answer is b because I learned this in 5th grade and I got it right