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erik [133]
3 years ago
12

How do weathering and deposition differ

Physics
1 answer:
makkiz [27]3 years ago
5 0
weathering refers to the actual breaking part of the rock or soil. deposition happens when the weathered and eroded material is deposited and finally comes to a stand still.
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Maxwell shoots a rubber band at his friend Jimmy. Which type of energy is converted into kinetic energy?
Leokris [45]

A stretched rubber band is storing <em>elastic potential energy. (A)</em>

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3 years ago
Which of the following distinguishes electromagnetic waves from mechanical waves
Ivan

Answer:

Explanation:

1. Mechanical waves require material medium for their propagation while electromagnetic waves do not require material medium for their propagation.

2. Mechanical waves can either be transverse or longitudinal while electromagnetic waves are transverse.(Transverse waves are waves in which the vibration of the particules of the medium is perpendicular to the direction of the motion of wave. E.g water waves, waves of a plucked string and all electromagnetic waves RIVUXG . Longitudinal waves are waves whose vibration are parallel to the direction of the motion of the medium e.g waves in strings, sound waves.e.t.c)

6 0
3 years ago
Power is equivalent to the energy released divided by the time taken to release the energy. true false
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P=E/t
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3 0
3 years ago
Please help me out !!
blagie [28]
I think the answer would be letter a
4 0
2 years ago
Spiral fracture of bone: Spiral fracture of bone occurs due to twisting of the limb, and is a very common skiing accident. The f
Pavlova-9 [17]

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

<u>a) Determine the principal stresses and shear stress</u>

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution

3 0
3 years ago
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