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VladimirAG [237]
3 years ago
14

838th

Chemistry
1 answer:
dangina [55]3 years ago
5 0

Answer:

Different liquid

Explanation:

<em>The independent variable in the investigation is the different liquid given to the plants.</em>

<u>The independent variable in an experimental investigation is the variable that is supplied by the researcher which directly affects the main variable being measured during the investigation. In other words, the independent variable is a variable that directly affects the dependent variable.</u>

In this case, the dependent variable would be growth determining factors in plants such as height, biomass, number of leaves, etc. while the independent variable would be the different types of liquid given to the plants.

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Which of the following values displays the pH of an acid? <br> A. 3<br> B. 12
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A pH of 7 or lower makes something an acid so it would be 3
3 0
3 years ago
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What is an investigation which all conditions are controlled
marshall27 [118]
It is a controlled experiment
4 0
3 years ago
James mixed Barium and oxide. what does he get? how does it work?
kherson [118]

Answer: Barium Oxide

We know that:

James mixed Ba + O²

Now, let's see what will happen when he does mix it.

The Barium will give it's electrons up to the oxide.

The Oxide and Barium will both reach noble gas status.

In the end, James will get Barium Oxide.

Best of Luck!

5 0
3 years ago
In a solution of H2SO4, rank the concentration of H2SO4, H+, SO42- from highest concentration to lowest concentration.
Softa [21]

Answer:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

Explanation:

H₂SO₄ is a strong acid, which means that most of it ionizes in aqueous solution.

Since it is a diprotic acid (two hydrogen ions) its ionization occurs in two steps:

  • H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)

  • HSO₄⁻ (aq) → H⁺(aq) + SO₄²⁻(aq)

Thus, almost all H₂SO₄ has ionized and its final concentration is almost nothing.

After the first ionization, the conentrations of H⁺(aq) and HSO₄⁻ are equal but by the second ionization more H⁺ ions are produced along with SO₄⁻.

You can show it as one step dissociation, assuming 100% dissociation (given this is a strong acid):

By the stequiometry you can build this table:

                 H₂SO₄ (aq) → 2H⁺(aq) + SO₄²⁻(aq)

Initial                A                 0              0

Change           - x               +2x          +x

Equilibrium       A - x           2x             x

As explained, A - x is very low, and 2x is twice x. Thus,

The rank of the concentrations from highest to lowest is:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

5 0
3 years ago
A gas mixture contains 0.800 mol of N2, 0.200 mol of H2, and 0.150 mol of CH4. What is the mole fraction of H2 in the mixture?
Blababa [14]

Answer:

0.1739

Explanation:

0.800 mol of N2

0.200 mol of H2

0.150 mol of CH4

Total moles of the mixture = 0.8 + 0.2 + 0.150 = 1.150 mol

Mole fraction of H2 = Number of moles of H2 /  Total moles

Mole Fraction = 0.2 / 1.150 = 0.1739

4 0
3 years ago
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