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Alika [10]
2 years ago
8

indigestion tablets neutralise acid in the stomach. what does this tell you about indigestion tablets?

Chemistry
1 answer:
Black_prince [1.1K]2 years ago
7 0

Answer:

It is basic.

Explanation:

Bases can neutralize acids.

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What is one reason that scientists who study weather need extremely advanced technology?
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Answer: C) To monitor weather event restricted several days in advance.

Explanation:

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3 years ago
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An oil tanker spills a large amount of oil near the ocean shoreline. Which application of chemistry would best solve this proble
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I have heard they can use hair is stocking or nets to absorb the oil out of the water
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3 years ago
Balance the following equation:<br> K+ H2O + H2 + KOH
alex41 [277]

Answer:

2K + 2H2O → H2 + 2KOH

Explanation:

Find how many atoms you have on both sides then add 2 to both sides.

Reactant:       Products:

K: 1+1=2                K: 1+1=2

H: 2+2=4             H: 3+1=4

O: 1+1=2                O: 1+1=2

Therefore it is balanced. Hope this helps

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2 years ago
What is the density of a liquid if it has a mass of 12.9g ?
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4 0
3 years ago
0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati
erastova [34]

Answer:

[Ag^{+}]=4.2\times 10^{-2}M

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]

[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}

Now,

Ag_{2}CrO_4(s) \leftrightharpoons  2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}

[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

                       

7 0
3 years ago
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