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Murljashka [212]
3 years ago
10

What is the angular momentum L of a rotating wheel with mass m, radius r, moment of inertia I, angular velocity ω, and velocity

v of its outer edge? A) mvr B) mωr C) Iω D) mIω
Physics
2 answers:
Angelina_Jolie [31]3 years ago
6 0
<span>The angular momentum L of a rotating wheel with mass m, radius r, moment of inertia I, angular velocity ω, and velocity v of its outer edge:

</span><span>C) Iω</span>
Mrrafil [7]3 years ago
5 0
The angular momentum L of a rotating wheel with mass m, radius r, moment of inertia I, angular velocity ω, and velocity v of its outer edge is "lω<span>". The correct option among all the options that are given in the question is the first option or option "C". I hope that the answer has helped you.</span>
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Directions: Select ALL the correct answers.
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Definitely D. The brakes on a bike rub against the wheel. Not sure about the others.
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Why all traveller prefer to travel easily in the morning and night and not when the sun is hot​
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You collect some more data on that horse at a later time interval, but now you are measuring thehorse’s velocity, not its positi
Monica [59]

Answer:

a)  x(t) = 10t + (2/3)*t^3

b) x*(0.1875) = 10.18 m

Explanation:

Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.

Given:

- v(t) = 10 + 2*t^2 (radar gun)

- x*(t) = 10 + 5t^2 + 3t^3  (our coordinate)

Find:

-The position x of horse as a function of time t in radar system.

-The position of the horse at x = 2m in our coordinate system

Solution:

- The position of horse according to radar gun:

                              v(t) = dx / dt = 10 + 2*t^2

- Separate variables:

                              dx = (10 + 2*t^2).dt

- Integrate over interval x = 0 @ t= 0

                             x(t) = 10t + (2/3)*t^3

- time @ x = 2 :

                              2 = 10t + (2/3)*t^3

                              0 = 10t + (2/3)*t^3 + 2

- solve for t:

                              t = 0.1875 s

- Evaluate x* at t = 0.1875 s

                              x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3

                              x*(0.1875) = 10.18 m

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Answer:

An “international employee” is defined as an employee of Stanford University whose work site is located.

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