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2 years ago

The wave property which is independent of all other properties is

1 answer:

3 0

The wave property which is independent of all other properties is THE VELOCITY OF A WAVE.
The velocity of a wave is defined as the distance moved by a cyclic motion per unit time. The velocity of a wave is determined by the properties of the medium through which it moves; it does not not depend on the properties of the wave itself.

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At t = 0 the switch S is closed with the capacitor uncharged. If C = 50 F,  = 20 V, and R = 4.0 k, what is the charge on the

gulaghasi [49]

Hello!

Recall the equation for the current in an RC circuit as a capacitor is charging:
$i(t) = \frac{\epsilon}{R}e^{-\frac{t}{RC}}$

i(t) = Current as a function of time (2.0 mA)

ε = Emf of voltage source (20V)
R = Resistance of resistor (4kΩ)

C = Capacitance of capacitor (50 μF)

We can solve for the time at which the current in the circuit decreases to 2.0 mA by plugging in the given values and solving for 't'.

$0.002 = \frac{20}{4000} e^{-\frac{t}{(4000)(0.00005)}}\\\\0.002 = 0.005 e^{-\frac{t}{(4000)(0.00005)}$

Solve:
$.4 = e^{-\frac{t}{0.2}}\\\\ln(.4) = -\frac{t}{0.2}\\\\t = -0.2(ln(.4)) = 0.1833 s$

Now, we can solve for the charge on the capacitor using the equation for charge of a charging capacitor:
$q(t) = C\epsilon(1 - e^{\frac{-t}{RC}})$

Plug in the given values and the time we solved for.

$q(t) = (0.00005)(20)(1 - e^{\frac{-0.1833}{(4000)(0.00005)}}) \\\\q(t) = 0.0006 = \boxed{600 \mu C}$

5 0

2 years ago

The constellation Canis Minor has a binary star system consisting of Procyon A and Procyon B. Procyon A, at 3×1030kg, has 2.5 ti

denis-greek [22]

This question involves the concepts of Newton's Law of Gravitation and mass.

The force on Procyon A from Procyon B will be "equal" to the force on Procyon B from Procyon A, which has a value of "3.75 x 10²⁶ N".

Applying Newton's Law of Gravitation, we can find the force on Procyon A from Procyon B, which is equal to the force on Procyon B from Procyon A:

$F=\frac{Gm_1m_2}{r^2}$

where,

F = force = ?

G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = mass of Procyon A = 3 x 10³⁰ kg

m₂ = mass of Procyon B = (2.5)(3 x 10³⁰ kg) = 7.5 x 10³⁰ kg

r = distance between them = 2 x 10¹² m

Therefore,

$F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(3\ x\ 10^{30}\ kg)(7.5\ x\ 10^{30}\ kg)}{(2\ x\ 10^{12}\ m)^2}$

Learn more about Newton's Law of Gravitation here:

brainly.com/question/17931361?referrer=searchResults

6 0

2 years ago

A closely wound, circular coil with radius 2.50 cmcm has 740 turns. Part A What must the current in the coil be if the magnetic

Vika [28.1K]

Answer:

The current in the coil is 4.086 A

Explanation:

Given;

radius of the circular coil, R = 2.5 cm = 0.025 m

number of turns of the circular coil, N = 740 turns

magnetic field at the center of the coil, B = 0.076 T

The magnetic field at the center of the coil is given by;

$B = \frac{N\mu_o I}{2R}$

where;

μ₀ is permeability of free space = 4 x 10⁻⁷ m/A

I is the current in the coil

R is radius of the coil

N is the number of turns of the coil

The current in the circular coil is given by

$B = \frac{N\mu_o I}{2R} \\\\I = \frac{2BR}{N\mu_o} \\\\I =\frac{2*0.076*0.025}{740*4\pi*10^{-7}} \\\\I = 4.086 \ A$

Therefore, the current in the coil is 4.086 A

3 0

3 years ago

Match the concepts in Column 1 to the definitions and explanations in Column 2.

Akimi4 [234]

Answer:

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3 0

2 years ago

पत्र- अपने क्षेत्र की सड़कों की बुरी दशा की जानकारी देते हुए और उन्हें ठीक कराने की प्रार्थना करते हुए नगर निगम अधिकारी को पत्र

Ksivusya [100]

Answer:

पत्र- अपने क्षेत्र की सड़कों की बुरी दशा की जानकारी देते हुए और उन्हें ठीक कराने की प्रार्थना करते हुए नगर निगम अधिकारी को पत्र लिखिए |

5 0

2 years ago