Answer:
This is true,the rod with smaller elastic modulus will stretch more than larger elastic modulus.
Explanation:
σ=E*ε
ε=δ/L
σ=E*δ/L
δ=(σ*L)/E
σ=F/A
δ=(F*L)/(A*E)
As Force,Area and Length is same
δ∞1/E
From the expression as E increase δ will be small,so there will be more stretch for smaller elastic modulus.
They protested by marching in the streets.
Answer:
3. 5.0N/kg
Explanation:
Gravitational field strength = gravitational force/mass of astronaut = 350N/70kg = 5.0N/kg
Answer:
Law 1. A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.
Law 2. A body acted upon by a force moves in such a manner that the time rate of change of momentum equals the force.
Law 3. If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction.
