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aliina [53]
3 years ago
15

What is the v-t graph area at the

Physics
1 answer:
Alex73 [517]3 years ago
4 0
The correct answer is at the uniform motion
You might be interested in
The s.I unit of R so that the equation velocity= R × density S dimensionally correct R is a constant
Leviafan [203]

Answer:

R = m⁴/kg . s

Explanation:

In this case, the best way to solve this is working with the units in the expression.

The units of velocity (V) are m/s

The units of density (d) are kg/m³

And R is a constant

If the expression is:

V = R * d

Replacing the units and solving for R we have

m/s = kg/m³ * R

m * m³ / s = kg * R

R = m * m³ / kg . s

<h2>R = m⁴ / kg . s</h2>

This should be the units of R

Hope this helps

5 0
3 years ago
Express the number in scientific notation: 4/100
ankoles [38]

Answer:

4*10^-2

Explanation:

for the scientific notation the first number must be between 1 and 10, so in this case it is 4. 4/100 is also equal to 0.04, and if we could the number of places before 4, there are two, therefore 4 times 10 to the power of -2

5 0
3 years ago
Identical balls are dropped from the same initial height and bounce back to half the initial height. In Case 1, the ball bounces
Kitty [74]

Answer:

<em>1. c. Same in both</em>

<em>2. a. Case 1</em>

<em></em>

Explanation:

1. The balls are identical in all sense, which means that if they are dropped from the same height, they should posses the same kinetic energy just before they collide with either the concrete floor or the stretchy rubber. Also, since they reach the same height when they bounced of the concrete floor or the piece of stretchy rubber, it means that they posses the same amount of kinetic energy at this point. Since their kinetic energy at these two points are the same, and they have the same masses, then this means that their momenta at these two instances will also be equal. Since all these is true, then the change in the momentum of the balls between the instance just before hitting the concrete floor or the stretchy rubber material and the instant the ball just leave the floor or the stretchy material is the same for both.

2. The ball that falls on the concrete will experience the greatest force, since the time of impact is small, when compared to the time spent by the other ball in contact with the stretchy rubber material; which will stretch, thereby extending the time spent in contact between them.

7 0
4 years ago
Can you have a changing speed and constant velocity?
igor_vitrenko [27]
No, a body can not have its velocity constant, while its speed varies. Rather, it can have its speed constant and its velocity varying. For example in a uniform circular motion.

7 0
3 years ago
A mass of 1.03 kilograms is placed on a horizontal frictionless surface against an uncompressed spring with spring constant 861.
Lelechka [254]

Answer:

5.522 m

Explanation:

Data provided:

Mass, m = 1.03 kg

spring constant, k = 861.1 N/m

Distance by which the spring is compressed, x = 0.36

Thus,

the energy stored in the spring = \frac{1}{2}kx^2

on substituting the values, we get

the energy stored in the spring =  \frac{1}{2}\times861.1\times0.36^2

now,

by the conservation of energy, we have

Potential energy gained by the mass =  Energy gained by the spring

or

mgh = \frac{1}{2}\times861.1\times0.36^2

where,

g is the acceleration due to the gravity

h is the maximum height reached by the mass before falling

on substituting the values in the above relation, we get

1.03 × 9.81 × h = \frac{1}{2}\times861.1\times0.36^2

or

h = 5.522 m

8 0
3 years ago
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