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3 years ago

12

Of the population of the United States is onese

2 answers:

Tomtit [17]3 years ago

8 0

Hey there!

(Pretty sure you meant “obese”) So, the correct answer is C. %33

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

NARA [144]3 years ago

6 0

Answer:

33% or 50% I hope that helped

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The loop is in a magnetic field 0.20 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A

love history [14]

Answer:

Part a)

$EMF = 14 \times 10^{-3} V$

Part b)

$EMF = 15.67 \times 10^{-3} V$

Explanation:

As we know that magnetic flux through the loop is given as

$\phi = B.A$

now we have

$\phi = B\pi r^2$

now rate of change in flux is given as

$\frac{d\phi}{dt} = B(2\pi r)\frac{dr}{dt}$

now we know that

$A = \pi r^2$

$0.285 = \pi r^2$

$r = 0.30 m$

Now plug in all data

$EMF = (0.20)\times 2\pi\times (0.30) \times (0.037)$

$EMF = 14 \times 10^{-3} V$

Part b)

Now the radius of the loop after t = 1 s

$r_1 = r_0 + \frac{dr}{dt}$

$r_1 = 0.30 + 0.037$

$r_1 = 0.337 m$

Now plug in data in above equation

$EMF = (0.20)\times 2\pi\times (0.337) \times (0.037)$

$EMF = 15.67 \times 10^{-3} V$

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3 years ago

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Answer:

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Genrish500 [490]

Answer:

The time it can operate between chargins in minutes is

$t=102.8 minutes$

Explanation:

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$K_R=\frac{1}{2}*I*w^2$

$I=\frac{1}{2}*m*r^2$

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$I=250 kg*m^2$

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$P=\frac{K_R}{t'}$

Solve to t'

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3 years ago