We will use two definitions to solve this problem. The first will be given by the conservation of energy, whereby the change in kinetic energy must be equivalent to work. At the same time, work can be defined as the product between the force by the distance traveled. By matching these two expressions and clearing for the Force we can find the desired variable.
![W = KE_f-KE_i](https://tex.z-dn.net/?f=W%20%3D%20KE_f-KE_i)
![Fd = \frac{1}{2}mv_f^2-\frac{1}{2} mv_i^2](https://tex.z-dn.net/?f=Fd%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv_f%5E2-%5Cfrac%7B1%7D%7B2%7D%20mv_i%5E2)
Thus the force acting on the sled is,
![F = \frac{m}{2s} (v_f^2-v_i^2)](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bm%7D%7B2s%7D%20%28v_f%5E2-v_i%5E2%29)
Replacing,
![F = \frac{8}{2(2.5)}(6^2-4^2)](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B8%7D%7B2%282.5%29%7D%286%5E2-4%5E2%29)
![F = 32N](https://tex.z-dn.net/?f=F%20%3D%2032N)
Therefore the Force acting on the sled is 32N
Answer:
Informal education is important because it can help individual to learn how to react and control situations.
It help individual to improve on its existing knowledge, new skills or ideas. This kind of education can happen any where and it can add values to the learner.
Explanation:
Informal education is a type of education that is learned from different life experiences, happenings outside a structured curriculum.
Informal education is important because it can help individual to learn how to react and control situations.
It help individual to improve on its existing knowledge, new skills or ideas. This kind of education can happen any where and it can add values to the learner.
I like French fries
My name is Razorclaw 017
Answer:
0.0195 m
Explanation:
= density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³
= diameter of hockey puck = 13 cm = 0.13 m
= height of hockey puck = 2.8 cm = 0.028 m
= density of mercury = 13.6 gcm⁻³ = 13600 kgm³
= depth of puck below surface of mercury
According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck
Weight of mercury displaced = Weight of puck
![\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m](https://tex.z-dn.net/?f=%5Crho%20_%7Bm%7D%20%280.25%29%28%5Cpi%20d_%7Bp%7D%5E%7B2%7D%20d%20%29%20g%20%3D%20%5Crho%20_%7Bp%7D%20%280.25%29%28%5Cpi%20d_%7Bp%7D%5E%7B2%7D%20h_%7Bp%7D%20%29%20g%5C%5C%5Crho%20_%7Bm%7D%20%28%20d%20%29%20%3D%20%5Crho%20_%7Bp%7D%20%28%20h_%7Bp%7D%20%29%5C%5C%2813600%29%20d%20%3D%20%289450%29%20%280.028%29%5C%5Cd%20%3D%200.0195%20m)
Answer: It can only match if you make it.
Explanation: