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Answer:</h3>
Chlorine gas (Cl₂)
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Explanation:</h3>
- According to the Graham's law of diffusion, the diffusion rate of a gas is inversely proportional to the square root of its density or molar mass.
- Therefore, a lighter gas will diffuse faster at a given temperature compared to a heavy gas.
- Consequently, the heavier a gas is then the denser it is and the slower it diffuses at a given temperature and vice versa.
In this case we are given gases, CI₂
, H₂,He and Ne.
- We are required to identify the gas that will diffuse at the slowest rate.
- In other words we are required to determine the heaviest gas.
Looking at the molar mass of the gases given;
Cl₂- 70.91 g/mol
H₂- 2.02 g/mol
He - 4.00 g/mol
Ne- 20.18 g/mol
Therefore, chlorine gas is the heaviest and thus will diffuse at the slowest rate among the choices given.
Answer:- 23.8 kJ of heat is required to raise the temperature of water.
Solution:- We have been given with grams of water, it's initial and final temperature and asked to calculate the heat required to raise it's temperature. Here, lower degree C water is changing into higher degree C water. So, the formula used to calculate the heat is:
Where, q is the heat energy, m is mass, c is specific heat of water and delta T is change in temperature.
m = 100 grams
= 82 - 25 = 57 degree C
q=?
Let's plug in the values in the formula and do the calculations:
q = 23848.8 J or 23.8 kJ
So, 23.8 kJ of heat is required to raise the temperature of 100 g of water from 25 to 82 degree C.
Answer:
62.98 % of the sample of hydrate is water
Explanation:
Step 1: Data given
Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams
After heating, the mass of the sample is 0.750 g
Molar mass H2O = 18.02 g/mol
Step 2: Calculate mass of water
Mass water = mass of hydrate - mass of sample after heating
Mass water = 2.026 grams - 0.750 grams
Mass water = 1.276 grams
Step 3: Calculate mass % percent of water
Mass % of water = (mass of water / total mass hydrate) * 100 %
Mass % of water = (1.276 grams / 2.026 grams) *100 %
Mass % of water = 62.98 %
62.98 % of the sample of hydrate is water
Solids-
cooked spinach, salmon, or artichokes.
liquids-
urine or milk.
Answer:
Equilibrium will be shifted towards NO2 as it has the most of the moles in the reaction.
Explanation:
Hello there!
In this case, according to the equilibrium reaction between NO2 and N2O4, we are able to write:
We can recall the LeCha-telier's principle to realize that the increase of volume promotes the formation of the most of the moles, this is for NO2 because it has a coefficient of 2 and N2O4 a coefficient of 1; in such a way, we infer that the addition of argon, to increase the pressure, will shift the equilibrium towards NO2.
Regards!