Answer:
The mass percent of potassium is 39%
Option C is correct
Explanation:
Step 1: Data given
Atomic mass of K = 39.10 g/mol
Atomic mass of H = 1.01 g/mol
Atomic mass of C = 12.01 g/mol
Atomic mass of O = 16.0 g/mol
Step 2: Calculate molar mass of KHCO3
Molar mass KHCO3 = 39.10 + 12.01 + 1.01 + 3*16.0
Molar mass KHCO3 = 100.12 g/mol
Step 3: Calculate mass percent of potassium (K)
%K = (atomic mass of K / molar mass of KHCO3) * 100%
%K = (39.10 / 100.12) * 100%
%K = 39.05 %
The mass percent of potassium is 39%
Option C is correct
Molecular equation
Hg₂(NO₃)₂ (aq) + KI(aq) ⇒Hg₂I₂(s) + 2KNO₃(aq)
Total Ionic equation
Hg²⁺(aq) + 2NO³⁻(aq) + 2K⁺aq) ⇒Hg₂I₂(s) + 2K⁺(aq) + NO³⁻ (aq)
Net Ionic equation
Hg²⁺(aq) + 2I⁻(aq) ⇒ Hg₂I₂(s)
<h3>What is the molecular equation?</h3>
Sometimes, a balanced equation is all that is used to refer to a chemical equation. Any ionic substances or acids are represented using their chemical formulas as neutral compounds in a molecular equation. Each substance's state is described in parenthesis after the formula. A complete ionic equation also contains the spectator ions, whereas a net ionic equation just displays the chemical species that are involved in a reaction.
The steps listed below can be used to determine the net ionic equation for a specific reaction:
Include the states of each chemical in the balanced molecular equation for the reaction.
To know more about the molecular equation, visit:
brainly.com/question/14286552
#SPJ4
When a red blood cell<span> is </span>placed<span> in a </span>hypertonic solution<span>, it shrinks as water is drawn
</span> cells<span> change size when </span>placed<span> in </span>solution<span> with different </span>salt<span> concentration is due </span>
Answer:
A chemical reaction produces formaldehyde, with a chemical formula of CH2O. Carbon is in Group 4A, oxygen is in Group 6A, and hydrogen is in Group 1A on the periodic table. In one to two sentences, can you describe the bonds in a molecule of formaldehyde in terms of valence electrons?
Explanation:
Answer: Three groups bound to it with no lone pairs
i think...
