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2 years ago

Which is a saturated solution?

Chemistry

2 answers:

BlackZzzverrR [31]2 years ago

7 0

Answer:

The term saturated solution is used in chemistry to define a solution in which no more solute can be dissolved in the solvent.

Viktor [21]2 years ago

3 0

Answer: a solution containing the maximum amount of solute dissolved in the solvent

Explanation:

You might be interested in

How does a wave get taller as

Anarel [89]

The reason why a wave get taller as it gets closer to shore is that the shallow water at the bottom of the wave makes the wave length smaller. Option B

A wave is a disturbance that occurs along a medium which transmits energy. Now we now that waves travel from place to place. The horizontal distance that is travelled by a wave is what we call the wavelength of the wave.

As the wave approaches the shore, the wave tends to slow down because it is dragged from beneath. In the process, the wave grows taller. Thus, the reason why a wave get taller as it gets closer to shore is that the shallow water at the bottom of the wave makes the wave length smaller. Option B

Learn more about wavelength:brainly.com/question/13533093

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4 0

10 months ago

Please solve quickly!!!

Maurinko [17]

Answer:

18 oxygen atoms

Explanation:

in order to from the 6 molecules carbon dioxide and 6 molecules of water you will have a total of 18 oxygen atoms

3 0

3 years ago

If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte

Assoli18 [71]

Answer:

$m=0.127g$

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

$k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}$

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

$m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g$

Best regards.

6 0

2 years ago

An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of

Lorico [155]

Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of water = 0.3 kg = 300 grams

Temperature of water = 20°C

Mass of alloy = 0.090 kg

Initial temperature of alloy = 55 °C

The final temperature = 25°C

The specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate the specific heat of alloy

Qlost = -Qwater

Qmetal = -Qwater

Q = m*c*ΔT

m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)

⇒ mass of alloy = 90 grams

⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED

⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C

⇒ mass of water = 300 grams

⇒ c(water) = the specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C

c(alloy) = 2.324 J/g°C

The specific heat of the alloy is 2.324 J/g°C

3 0

3 years ago

How do I find the slope of this graph? Is it even possible?

nasty-shy [4]

Answer:

Not exactly But you can take the slope of the curved portion and the slope of the flatline.

It wont do you much good since your working for absorbance but if you ever see something like a temperature change you can use the slope(s) to find freezing points/melting

Explanation:

If you need to submit a slope you could use a best fit which is just point to point or you could break it up like i mentioned

4 0

2 years ago