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777dan777 [17]
3 years ago
15

How many moles of a gas sample are in a 20.0 L container at 373 K and 203 kPa? The gas constant is 8.31 L−kPa/mol−K. A)0.33 mole

B)0.65 mole C)1.30 moles D)3.05 moles
Chemistry
1 answer:
12345 [234]3 years ago
4 0

Answer:

Option (C) 1.30 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 20L

Temperature (T) = 373K

Pressure (P) = 203 kPa

Gas constant (R) = 8.31 L.kPa/mol.K.

Number of mole (n) =...?

The number of mole of the gas in the container can obtained by applying the ideal gas equation as illustrated below:

PV = nRT

Divide both side by RT

n = PV /RT

n = 203 x 20 / 8.31 x 373

n = 1.30 mole.

Therefore, 1.30 mole of the gas is present in the container.

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5000 cal X 4.184 J/cal =

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20,920 jules

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What happens to the temperatures when we have direct sunlight vs indirect sunlight?
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Explanation:

When we have direct sunlight, the temperature is higher compared to indirect sunlight.

Direct sunlight is usually overhead whereas indirect sunlight is at an angle to the surface.

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3 years ago
1. How many molecules are in 240g of sulfuric acid?
Soloha48 [4]

Answer:

14.8 × 10²³ molecules

Explanation:

Given data:

Mass of sulfuric acid = 240 g

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Number of moles of sulfuric acid

<em>Number of moles = mass/ molar mass</em>

Number of moles =  240 g/ 98 g/mol

Number of moles = 2.45 mol

Number of molecules:

1 mole = 6.022 × 10²³ molecules

2.45 × 6.022 × 10²³ molecules

14.8 × 10²³ molecules

3 0
3 years ago
HELP!!!!!<br> i need help on this chemistry question
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Answer: electronic configuration

Explanation:

8 0
3 years ago
you wish to make a 0.161 m hydroiodic acid solution from a stock solution of 3.00 m hydroiodic acid. how much concentrated acid
mestny [16]

5.367 ml of the concentrated acid must be added to obtain a total volume of 100 ml of the dilute solution.

Dilution is defined as the process in which the concentration of a sample is decreased by adding more solvent. The dilution formula is given below.

C₁V₁ = C₂V₂

where C₁ = initial concentration of sample = 3.00 m

V₁ = initial volume of sample

C₂ = final concentration after dilution = 0.161 m

V₂ = total final volume after dilution = 100 ml

Plug in the values to the formula and solve for the volume of the concentrated acid that must be added.

C₁V₁ = C₂V₂

3.00 m (V₁) = 0.161 m (100 ml)

V₁ = 5.367 ml

Learn more about dilution here: brainly.com/question/1615979

#SPJ4

3 0
1 year ago
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