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Vanyuwa [196]
3 years ago
4

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
1 answer:
Mila [183]3 years ago
3 0

Answer:

C) from 4.5 to 5.0 seconds

Explanation:

The graph shows the distance of the ball from the initial point (y-axis) against the time (x-axis).

In such graph, the speed of the ball corresponds to the slope of the curve, since it is equal to the ratio between the distance travelled (increment in the y-axis) and time taken (increment in the x-axis):

v=\frac{\Delta y}{\Delta x}=\frac{d}{t}

Therefore, we can say that the object is moving when the slope of the curve is not zero: when the slope of the curve is zero, instead, the object is at rest.

From the graph, we observe that between t=4.5 s and t=5.0 s the slope of the curve is zero, because the curve is horizontal. This means that the speed is zero, so the object is not moving.

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It would have to be c because it is a chemical change. your welcome!!!!!
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In the diagram, a force of 20 newtons is applied to a block. The block is in dynamic equilibrium. What is the magnitude and dire
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A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is
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1) At the moment of being at the top, the piston will not only tend to push the penny up but will also descend at a faster rate at which the penny can reach in 'free fall', in that short distance. Therefore, at the highest point, the penny will lose contact with the piston. Therefore the correct answer is C.

2) To solve this problem we will apply the equations related to the simple harmonic movement, hence we have that the acceleration can be defined as

a = -\omega^2 A

Where,

a = Acceleration

A = Amplitude

\omega= Angular velocity

From a reference system in which the downward acceleration is negative due to the force of gravity we will have to

a = -g

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From the definition of frequency and angular velocity we have to

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f = \frac{1}{2\pi} \sqrt{\frac{g}{A}}

f = \frac{1}{2\pi} \sqrt{\frac{9.8}{4*10^{-2}}}

f = 2.5Hz

Therefore the maximum frequency for which the penny just barely remains in place for the full cycle is 2.5Hz

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3 years ago
How would the self-inductance, l, of a coil change if you would increase its radius by a factor of two and increase its length b
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The self-inductance of a coil will change by 8 times its original value by increasing its radius value by 2 and increasing the length of the coil by 2.

Self-Inductance: -

The definition of self-inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. In the instance of self-inductance, the circuit itself induces a voltage through the magnetic field produced by a changing current.

We know that the self-inductance of the coil is denoted by: -

L= µ *π*(r)^2*(N)^2*l

Where

L= Self-Inductance of the coil

µ= Magnetic Permeability Constant

r= Radius of the coil

l= Length of the coil

N= Number of turns of the coil

Here Self-inductance of the coil is directly proportional to the length of the coil and the square of the radius of the coil.

So,

On increasing the radius of the coil by a factor of 2 and the length of the coil by 2 the self-inductance of the coil increases by 8 times its original value.

Learn more about Self-Inductance here: -

" brainly.com/question/15293029 "

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