Answer:
i want coins sorry use a calculator or sum
Explanation:
kk
Answer is: $637.28; just did the math but i really don’t want to type it all out.
Answer:
COP = 3.828
W' = 39.18 Kw
Explanation:
From the table A-11 i attached, we can find the entropy for the state 1 at -20°C.
h1 = 238.43 KJ/Kg
s1 = 0.94575 KJ/Kg.K
From table A-12 attached we can do the same for states 3 and 4 but just enthalpy at 800 KPa.
h3 = h4 = hf = 95.47 KJ/Kg
For state 2, we can calculate the enthalpy from table A-13 attached using interpolation at 800 KPa and the condition s2 = s1. We have;
h2 = 275.75 KJ/Kg
The power would be determined from the energy balance in state 1-2 where the mass flow rate will be expressed through the energy balance in state 4-1.
W' = m'(h2 - h1)
W' = Q'_L((h2 - h1)/(h1 - h4))
Where Q'_L = 150 kW
Plugging in the relevant values, we have;
W' = 150((275.75 - 238.43)/(238.43 - 95.47))
W' = 39.18 Kw
Formula foe COP is;
COP = Q'_L/W'
COP = 150/39.18
COP = 3.828
Answer:
water rise = 22 mm
Explanation:
weight of packet IN AIR = 40 *9.81 =392.4 N
weight of packet IN WATER= 18 *9.81 =176.58 N
by Archimedi's principle
difference in weight = weight of displaced water
w_a - w_w = \rho_w v_d g
392.4 - 176.58 = 1000* v_d* 9.81
v_d = 0.022 m^3
v_d = A*H_rise
0.022 =1*H_rise
H_rise = 0.022 m = 22 mm
water rise = 22 mm
Answer:
Option A, World War II
Explanation:
During the period of industrial revolution around 1915-25, the chemical engineering has taken a new shape. During this period (i.e around the world war I), there was rise in demand for liquid fuels, synthetic fertilizer, and other chemical products. This lead to development of chemistry centre in Germany . There was rise in use of synthetics fibres and polymers. World war II saw the growth of catalytic cracking, fluidized beds, synthetic rubber, pharmaceuticals production, oil & oil products, etc. and because of rising chemical demand, chemical engineering took a new shape during this period
Hence, option A is the right answer