Answer:
A) 88.42 ohms
c) 0.5145 and - 5.77 db
Explanation:
A) Value of cut-off frequency = 12 kHz
capacitance of capacitor =0.15 microF
formula for cut-off frequency of a low-pass filter
making R the subject of the formula in other to get the resistance of the low pass filter resistor
R =
= 88.42 OHMS
attached is the solution for B and C
Answer:
He invented wind powered electrical generation in 1831.
I’m so sorry ii wish ii could help
Answer:
1. Shape factor is calculated.
2.Heat transfer rate is calculated.
3.Heat transfer per unit length is calculated.
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Answer:
Δr=20.45 %
Explanation:
Given that
Rake angle α = 15°
coefficient of friction ,μ = 0.15
The friction angle β
tanβ = μ
tanβ = 0.15
β=8.83°
2φ + β - α = 90°
φ=Shear angle
2φ + 8.833° - 15° = 90°
φ = 48.08°
Chip thickness r given as


r=0.88
New coefficient of friction ,μ' = 0.3
tanβ' = μ'
tanβ' = 0.3
β'=16.69°
2φ' + β' - α = 90°
φ'=Shear angle
2φ' + 16.69° - 25° = 90°
φ' = 49.15°
Chip thickness r' given as


r'=0.70
Percentage change


Δr=20.45 %