1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleks [24]
3 years ago
12

If a car is traveling westward at a constant velocity of 20m/s, what is the net force acting on the car?

Physics
1 answer:
STALIN [3.7K]3 years ago
7 0
40 miles of force i think
You might be interested in
ASAP pls answer right I will mark brainiest . All I know is 4. Is A
Sonja [21]

Answer:

Q1: B.2 Q2: B.Waxing crescent Q3: A.Waxing Gibbous

Explanation:

4 0
3 years ago
A block is held at rest against a wall by a force of magnitude F exerted at an angle theta from the horizontal, as shown in the
wel

Answers:

B.) F cos\theta=F_{n}

C.) F sin\theta=F_{g} \pm F_{f}

Explanation:

The image attached shows the way the force F is acting on the block. Now, if we draw a free body diagram of the situation and write the equations for the Net Force in X and Y, we will have the following:

Net Force in X:

-F_{n}+F cos\theta=0 (1)

Where:

F_{n} is the Normal force

F is the magnitude of the force exerted on the block

\theta is the angle

Net Force in Y:

F sin\theta \pm F_{f}-F_{g}=0 (2)

Where:

F_{f} is the Friction force (it is expresed with the \pm sign because this force may be up or down, we cannot know because the block is at rest)

F_{g} is the gravity force

Rewrittin (1):

F cos\theta=F_{n} (3) This is according to option B

Rewritting (2):

F sin\theta=F_{g}\pm F_{f} (3) This is according to option C

3 0
3 years ago
An air balloon is moving upward at a constant speed of 3 m/s. Suddenly a passenger realizes that she left her camera on the grou
frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

speed of balloon is u=3\ m/s

speed of camera u_1=20\ m/s

Initial separation between camera and balloon is d_o=5\ m

Suppose after t sec of  throw camera reach balloon then,

distance travel by balloon is

s=ut

s=3\times t

and distance travel by camera to reach balloon is

s_1=ut+\frac{1}{2}at^2

s_1=20\times t-\frac{1}{2}gt^2

Now

\Rightarrow s_1=5+s

\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t

\Rightarrow 5t^2-17t+5=0

\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}

\Rightarrow t=\dfrac{17\pm 13.747}{10}

\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is  t=0.3253\ s

velocity is given by

v=u+at

v=20-10\times 0.3253

v=16.747\ m/s

and position of camera is same as of balloon so

Position is =5+3\times 0.3253

=5.975\approx 6\ m

8 0
3 years ago
A bicycle wheel with radius 0.3 m rotates from rest to 3 rev/s in 5 s. What is the magnitude and direction of the total accelera
AlekseyPX

Answer:

Explanation:

Given

Radius of bicycle wheel r=0.3\ m

Initial angular velocity \omega _0=0

It rotates 3 revolution in 5 s therefore

\omega =2\pi 3=\6\pi =18.85\ rad/s

using \omega =\omega _0+\alpha t

where \alpha =angular\ acceleration

\omega =Final\ angular\ velocity

t=time

\alpha =\frac{18.85}{5}=3.77 rad/s^2

Total acceleration of any point will be a vector sum of tangential acceleration and centripetal acceleration

\omega at t=1

\omega =0+3.77\times 1=3.77 rad/s

a_c=\omega ^2\cdot r

a_c=(3.77)^2\cdot 0.3=4.26 m/s^2

Tangential acceleration a_t=\alpha \times r

a_t=3.77\times 0.3=1.13 m/s^2

a_{net}=\sqrt{a_t^2+a_c^2}

a_{net}=\sqrt{(1.13)^2+(4.26)^2}

a_{net}=4.41 m/s^2

                       

7 0
3 years ago
Imagine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and ra
pashok25 [27]

Here if we assume that there is no air friction on both balls then we can say

F = mg

now the acceleration is given as

F = ma = mg

a = g

so here both the balls will have same acceleration irrespective of size and mass

so we can say that to find out the time of fall of ball we can use

y = \frac{1}{2}gt^2

t = \sqrt{\frac{2y}{g}}

now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size

3 0
3 years ago
Other questions:
  • An observer is standing at a point balloon calculus find the rate at which
    14·1 answer
  • A wheel rotates about a fixed axis with a constant angular acceleration of 4.0 rad/s2. The diameter of the wheel is 40 cm. What
    11·1 answer
  • Help please! Science!
    11·2 answers
  • A river flows due east with a speed of 3.00 m/s relative to earth. The river is 80.0 m wide. A woman starts at the southern bank
    15·1 answer
  • You want to calculate the displacement of an object thrown over a bridge. Using -10m/s^2 for acceleration due to gravity, what w
    8·1 answer
  • Objects fall near the surface of the earth with a constant downward acceleration of 10 m/s2 . At a certain instant an object is
    11·1 answer
  • What can you infer about a wave with a long wavelength?
    9·2 answers
  • What is the weight of an object with a force of 35 pounds ?
    6·1 answer
  • At what rate is thermal energy being generated in the 2R-resistor when  = 12 V and R = 3.0 ?
    14·1 answer
  • A motorcycle is moving with the velocity of 72km/h. If the velocity reaches 40m/s after 0.5m calculate the acceleration
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!