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nexus9112 [7]
3 years ago
7

Complete the sentences to identify the trend in first ionization energies as one proceeds down the group 7A elements and explain

how this trend relates to the variation in atomic radii.
Complete the following sentences using this word bank:

a. increase
b. decrease
c. greater
d. smaller

1. Moving from F to I in group 7A, first ionization energies ____
2.Moving from F to I in group 7A, atomic radii ____
3. The relationship between atomic radii and first ionization energy going down a column is best explained by the fact that the greater the atomic radius, the ____ the electrostatic attraction of an outer electron for the nucleus and the ____ the ionization energy of the element.
Chemistry
1 answer:
Harrizon [31]3 years ago
3 0

Answer:

a)decrease

b)increase

c)smaller

d)smaller

Explanation:

Ionization energy decreases down the group due to increase in the atomic radius. The distance between the outermost electron and the nucleus increases hence the nuclear attraction for the outermost electrons become smaller and the ionization energy also become smaller as electrons are now easily removed from the outermost shell.

Hence the group of answer choices provided above.

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The chart with the information to answer this question may be found in other Brainly's link, so I attach it now.

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  • Z

Explanation:

To facilitate the accompaniment of the reasoning, I copy the data here:

Object     Motion

  X           3 units left, 3 units right

  Y           6 units right, 18 units right

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The <em>distance</em> is the scalar magnitude that indicates the total length of the path traveled.

The <em>displacement</em> is the vector that indicates how far the end point and the initial point are.

In order to calculate the distance, the displacement and the ratio r = distance/displacement, to check which object has a distance that is three times as great as its displacement, i.e. r = 3, we use this new chart:

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  X          3 units left, 3 units right        3 + 3 = 6       3 - 3 = 0            ∞

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The ratios were calculated dividing the distance by the displacement: distance / displacement.

For the object Z, that was 24 / 8 = 3. Thus, the object that has a distance that is three times as great as its displacement is the object Z.

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