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nexus9112 [7]
3 years ago
7

Complete the sentences to identify the trend in first ionization energies as one proceeds down the group 7A elements and explain

how this trend relates to the variation in atomic radii.
Complete the following sentences using this word bank:

a. increase
b. decrease
c. greater
d. smaller

1. Moving from F to I in group 7A, first ionization energies ____
2.Moving from F to I in group 7A, atomic radii ____
3. The relationship between atomic radii and first ionization energy going down a column is best explained by the fact that the greater the atomic radius, the ____ the electrostatic attraction of an outer electron for the nucleus and the ____ the ionization energy of the element.
Chemistry
1 answer:
Harrizon [31]3 years ago
3 0

Answer:

a)decrease

b)increase

c)smaller

d)smaller

Explanation:

Ionization energy decreases down the group due to increase in the atomic radius. The distance between the outermost electron and the nucleus increases hence the nuclear attraction for the outermost electrons become smaller and the ionization energy also become smaller as electrons are now easily removed from the outermost shell.

Hence the group of answer choices provided above.

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If 155 grams of potassium (K) reacts with 122 grams of potassium nitrate (KNO3), what is the limiting reagent?
GenaCL600 [577]
K:

m=155g
M=39g/mol

n = 155g / 39g/mol ≈ 3,97mol

KNO₃:

m=122g
M=101g/mol

n = 122g/101g/mol = 1,21mol

2K          +            10KNO₃  ⇒  6K₂O + N₂
2mol        :            10mol
3,97mol   :           1,21mol
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KNO₃ is limiting reagent

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3 years ago
What observations can you make about this group of people? Name one inference you can make from your observations.​
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7 0
3 years ago
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You wish to make a 0.375 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid
cluponka [151]

We need to add 2.09 mL of concentrated acid to obtain 75 mL of 0.335 M HBr solution.

You are performing a dilution of HBr going from a concentration of 12M to 0.335M, and you want to end up with a final volume of 75 ml of the dilute solution.

Consider the dilution formula: M1V1 = M2V2.

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M2 = the molarity of the diluted solution,

V2 = the final volume of the diluted solution.

In this case, we need to determine V1, which is the volume of the stock solution used to prepare the diluted sample. With this knowledge, we can plug our numbers into the equation and we obtain the following:

(12 mol/L)*V1 = (0.335mol/L)*(0.075L).

Keeping in mind that molarity is the moles of a substance in one liter of solution, we will use mol/L instead of M. By doing this, we are reminded that in order to use this equation, we must convert 75 mL into units of liters.

After rearranging the equation and solving for V1, we find that V1 = 0.00209L.

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Learn more about molarity here: brainly.com/question/23243759

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2 years ago
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Answer:

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Explanation:

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Can someone help me, please?
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The answer to this question is: B) 3+
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