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ch4aika [34]
3 years ago
3

Stu wanted to calculate the resistance of a light bulb connected to a 4.0-V battery, with a resulting current of 0.5 A. He used

the formula R = VI and obtained an answer of 2 . Was Stu’s answer correct? How do you know?
Physics
2 answers:
Fiesta28 [93]3 years ago
6 0

Answer: no, Stu's answer was incorrect.

Explanation:

The correct formula that relates current, resistance and voltage in a circuit is given by Ohm's law:

V=RI

or

R=\frac{V}{I}

where

V is the voltage in the circuit

I is the current

R is the resistance

In this circuit, the voltage is V=4.0 V, and the current is I=0.5 A, therefore the resistance of the circuit is

R=\frac{V}{I}=\frac{4.0 V}{0.5 A}=8 \Omega

maksim [4K]3 years ago
6 0

Sample Response: Stu's answer was incorrect. According to Ohm's law, R = V/I. This is the equation that should be used to obtain the correct answer, which is 8 ohms.

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The ant would drag the sugar 500m


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A positively charged body exerts an electric field that causes a positively charged particle to move away from it. If work is do
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Answer:

b. electric potential energy.

Explanation:

The energy required to move a charge against the electric field is known as the electric potential energy. As in above case positively charged body is exerting an electric field on the positive charge. As the same charges repel so the charge tend to move away. In order to push it towards the body we need a work done. As it is hard to push the positive charged particle towards the positive electric field. So in the cases like these particle occupies the electric potential energy.

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An atom with two protons, three neutrons and two electrons would have a mass of about how many atomic mass units?
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A test charge is placed at a distance of 2.5 × 10-2 meters from a charge of 6.4 × 10-5 coulombs. What is the electric field at t
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Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance. 

E = kQ / d²

k = 9 x 10^9 N-m²/C²
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d = 2.5 x 10^-2 m

Substituting the given values to the equation, we have:
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8 0
3 years ago
Read 2 more answers
Which of the following graphs best represents the relationship between the gravitational potential energy of a freely falling ob
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Answer:

The last graph.

Explanation:

Gravitational potential energy is the energy possessed by a body at a given height from the Earth's surface.

The formula to find the gravitational potential energy is given as:

U=mgh

Where, 'U' is the gravitational potential energy.

'm' is the mass of the body.

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'h' is the height of the body above the Earth's surface.

So, from the above equation, it is clear that, gravitational potential energy is directly proportional to the height. So, as height increases, the gravitational potential energy increases. At the surface of Earth, where, height is 0, the gravitational potential energy is also zero.

Therefore, the correct graph is a straight line with positive slope and passing through the origin. So, the last option is the correct one.

3 0
3 years ago
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