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2 years ago

How is the kelvin temperature of a substance related to the average kinetic energy of its particles?

Physics

1 answer:

Gwar [14]2 years ago

4 0

Answer:

The answer to your question is below

Explanation:

T = °K

Kinetic energy

Temperature is the measure of the kinetic energy of molecules, the higher the temperature the higher the kinetic energy.

When the temperature is 0°K the molecules will not move and the kinetic energy will be zero.

If the temperature is 373°K the molecules will move fast and the kinetic energy will also be high.

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When is the universal theme of a story often revealed?

elena-14-01-66 [18.8K]

It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>

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2 years ago

Read 2 more answers

PLEASE HELP ME PLEASE

Afina-wow [57]

Answer:

For A

Displacement= 1/2*3*6= 9m

For B

Displacement= 1/2*4*4= 8m

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2 years ago

Suppose that you are swimming in a river while a friend watches from the shore. In calm water, you swim at a speed of 1.25 m/s .

aliya0001 [1]

Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.

Explanation:

Let <em>S</em> be the speed of the swimmer, given as 1.25 m/s

Let $S_{0}$ be the speed of the river's current given as 1.00 m/s.

Note that this speed is the magnitude of the velocity which is a vector quantity.

The direction of the swimmer is upstream.

Hence the resultant velocity is given as, $S_{R}$ = S — S 0 $S_{0}$

$S_{R}$ = 1.25 — 1

$S_{R}$ = 0.25 m/s.

Therefore, the observing friend will see the swimmer moving at a speed of 0.25 m/s due to resistance produced by the current of the river.

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2 years ago

Which of the following best represents a chemical reaction?

Sonja [21]

Answer:

The answer to your question should be D.

Explanation:

reactants are on the laft side of arrow and products are on right side of arrow

7 0

2 years ago

A river 1.00 mile wide flows with a constant speed of 1.00 mph. A man can row a boat at 2.00 mph. He crosses the river in a dire

gladu [14]

To solve this problem we will apply the geometric concepts of displacement according to the description given. Taking into account that there is an initial displacement towards the North and then towards the west, therefore the speed would be:

$V_T^2=v_N^2-v_W^2$

$V_T = \sqrt{v_N^2-v_W^2}$

Travel north 2mph and west to 1mph, then,

$V_T = \sqrt{2^2-1^2}$

$V_T = \sqrt{3}$

The route is done exactly the same to the south and east, so make this route twice, from the definition of speed we have to

$v= \frac{\Delta x}{t}$

$t = \frac{\Delta x}{v}$

$t = \frac{2*(1mile)}{\sqrt{3}mph}$

$t = 1.15hour$

Therefore the total travel time for the man is 1.15hour.

3 0

2 years ago