Answer: a) anode
b) positive
c) cathode
d) anode to cathode
Explanation:
Galvanic cell is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.
In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode. Thus the electrons are produced at anode and travel towards cathode.
Due to loss of electrons at anode, positive charge in concentrated in anode and negative charge is concentrated in cathode. To balance these charges , positive ions or cations from salt bridge move towards cathode and negative ions or anions from salt bridge move towards anode.
The balanced two-half reactions will be:
Oxidation half reaction :
Reduction half reaction :
Thus the overall reaction will be,
8) 21.504 liters of gas
9) 122.5 g
10) 6.022*10^23
Explanation:
8)
1 mole= 22.4 liters
to calculate the volume of gas of 0.960 moles of CH4
22.4*0.960/1
= 21.504 liters of gas
9)
2.0 mole*18.02 g/ 1 mole
=122.5 g
10)
2.0 l * 1 mole/22.4 l
6.022*10^23
Answer:
Điều này là kết quả của quá trình hydrat hóa các ion: lực hút của các phân tử nước đối với Công thức phản ứng của kali hydroxit với các ion nước. Phản ứng có thể được viết dưới dạng KOH (s) → K⁺ (aq) + OH⁻ (aq).
Explanation:
Based on the diagram shown in the attached file
R = Radius of the sphere
a = Lattice constant
Using pythagoras theorem for the right angled triangle in figure 2
(4R)^2 = a^2 + a^2
16(R^2) = 2(a)^2
Solving the above equation
a=2R√2
To prove that the Atomic Packing factor is 0.74
Let the volume of atom in a unit cell be Vs
Total unit cell volume, Vc
Vc = a^3
Vc =(2R√2)^3
Vc=16R^3 √2 =22.63R^3
Since there are 4 atoms in the FCC unit cell
Vs=4*(4/3 πR^3)
Vs=5.33 πR^3
APF=(5.33 πR^3)/(22.63R^3 )
APF=0.74
Answer:
D) 20.0 atm
Explanation:
To solve this problem, we can apply Boyle's law, which states that:
"For a constant mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to the volume of the gas".
Mathematically:
where
p is the gas pressure
V is the volume of the gas
The equation can also be rewritten as
where in this problem:
is the initial pressure of the gas
is the initial volume of the gas
is the final volume of the gas
Solving for p2, we find the final pressure of the gas: