Answer:
Here's what I get
Explanation:
The reaction is an E1 elimination of an alcohol to form an alkene. It has three steps:
1. Protonation
The alcohol is protonated with aqueous sulfuric acid to convert it into a better leaving group.
2. Loss of the leaving group
A water molecule leaves in a unimolecular process to form a stable 3° carbocation.
3. Loss of an α-hydrogen
A water molecule removes an α-hydrogen, forming 2-methylpropene and regenerating the original hydronium ion.
D. details about what happening
Answer: I remember looking out of the car as we pulled up to the Frantz school.”
“I thought maybe it was Mardi Gras.”
“As we walked through the crowd, I didn’t see any faces.”
“[The school] looked bigger and nicer than my old school.”
“The crowd behind us made me think this was an important place.”
“It must be college, I thought to myself.
Explanation:
Answer: They belong to the same kingdom but different phyla.
Explanation:
Answer:
<span>Given mass of C is 32.0 grams
</span><span>Given mass of H is 8.0 grams
</span>Molar mass of C is 1212 g/mol
Molar mass of H is 1.01 g/mol
Thus
<span><span><span><span>32.0 grams of C </span><span>8.0 grams of H </span></span><span><span>→<span>3212</span>=2.66 moles of C</span><span>→<span>81.01</span>=7.92 moles of H</span></span></span><span><span><span>32.0 grams of C </span><span>→<span>3212</span>=2.66 moles of C</span></span><span><span>8.0 grams of H </span><span>→<span>81.01</span>=7.92 moles of H</span></span></span></span>
<span>When we divide 7.92 by 2.66 we obtain 2.977 which is approximately 3. This means that the ratio of atoms of </span><span>CC</span><span> to the atoms of </span><span>HH</span><span> is 1:3.</span>
<span>Thus, empirical formula for the compound is </span><span><span>C<span>H3</span></span><span>C<span>H3</span></span></span>.
<span>Molar mass of </span><span><span>C<span>H3</span></span><span>C<span>H3</span></span></span><span> is </span><span><span>1⋅12+3⋅1.01=15.03</span><span>1⋅12+3⋅1.01=15.03</span></span><span>. Since molar mass of the compound we have to find is </span><span>3030</span><span> g/mol we have tu multiply subscripts by 2.</span>
<span>Thus, final compound is </span><span><span><span>C2</span><span>H6</span></span><span><span>C2</span><span>H6</span></span></span>.
