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3 years ago

What gas is a product in the below chemical reaction?

Chemistry

1 answer:

daser333 [38]3 years ago

4 0

Answer: Sulfur dioxide is he gas formed in the chemical reaction below.

Explanation: The reaction between Acetic acid and Lithium hydrogen sulfite produces water, sulfur dioxide and lithium acetate. The balanced Chemical reaction is:

$HC_2H_3O_2(aq.)+LiHSO_3(aq.)\rightarrow H_2O(l)+SO_2(g)+LiC_2H_3O_2(aq.)$

The gas produced is sulfur dioxide when this reaction takes place.

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The pH of a solution prepared by the addition of 100mL 0.002M HCL to 100mL distilled water is closest to:

IRISSAK [1]

Answer:

d.3.0

Explanation:

Step 1: Calculate the final volume of the solution

The final volume is equal to the sum of the volumes of the initial HCl solution and the volume of distilled water.

V₂ = 100 mL + 100 mL = 200 mL

Step 2: Calculate the final concentration of HCl

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂ = 0.002 M × 100 mL/200 mL = 0.001 M

Step 3: Calculate the pH of the final HCl solution

Since HCl is a strong acid, [H⁺] = HCl. We will use the definition of pH.

pH = -log [H⁺] = -log 0.001 = 3

7 0

3 years ago

What masses of iron(iii) oxide and aluminum must be used to produce 15.0 g iron? what is the maximum mass of aluminum oxide that

defon

1) Chemical reaction:

Fe2O3 + 2Al ---> Al2O3 + 2Fe

2) molar ratios

1 mol Fe2O3 : 2Al : 1 mol Al2O3 : 2 mol Fe

3) Convert 15.0 g of iron into moles

atomic mass Fe = 55.8 g/mol

moles = mass in grams / atomic mass = 15.0 g / 55.8 g/mol = 0.269 mol

4) Use proportions to determine the moles of Fe2O3, Al, and Al2O3

a) 1mol Fe2O3 / 2 mol Fe = x / 0.269 mol Fe

x =

=> x = 0.269 mol Fe * 1 mol Fe2O3 / 2 mol Fe = 0.134 mol Fe2O3

b) 2 mol Al / 2 mol Fe = x / 0.269 mol Fe

=> x = 0.269 mol Al

c) 2 mol Fe / 1 mol Al2O3 = 0.269 mol Fe / x

=> x = 0.269 mol Fe * 1 mol Al2O3 / 2 mol Fe

x = 0.134 mol Al2O3

5) Convert moles to grams

a) Fe2O3

molar mass Fe2O3 = 2* 55.8 g/mol + 3*16g/mol = 159.6 g/mol

mass = molar mass * number of moles

mass = 159.6 g/mol * 0.134 mol = 21.4 g

b) Al

atomic mass = 27.0 g/mol

mass = number of moles * atomic mass = 0.269 mol * 27.0 g/mol = 7.26 g

c) Al2O3

molar mass = 2 * 27.0 g/mol + 3*16.0 g/mol = 102.0g/mol

mass Al2O3 = numer of moles * molar mass = 0.134 mol * 102.0 g/mol = 13.7 g

Answers:

21.4 g Fe2O3

7.26 g Al

13.7 g Al2O3

6 0

3 years ago

How much NaOH (in grams) is needed to prepare 463 mL of solution with a pH of 10.020?

tino4ka555 [31]

Answer: $1.94\times 10^{-3}g$ of NaOH

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

Putting in the values:

$10.020=-\log[H^+]$

$[H^+]=9.55\times 10^{-11}$

$[H^+][OH^-]=10^{-14}$

$[OH^-]=\frac{10^{-14}}{9.55\times 10^{-11}}=1.05\times 10^{-4}M$

$NaOH\rightarrow Na^++OH^-$

$Molarity=\frac{moles\times 1000}{\text {Volume in ml}}$

$1.05\times 10^{-4}M=\frac{moles\times 1000}{463ml}$

moles = $4.86\times 10^{-5}$

Mass of $NaOH=moles\times {\text {Molar mass}}=4.86\times 10^{-5}\times 40=1.94\times 10^{-3}g$

Thus $1.94\times 10^{-3}g$ of NaOH is needed to prepare 463 mL of solution with a pH of 10.020

8 0

3 years ago

A student produces 1.34g of mgnh4po4*6h2o (mm =245.1 g/mol) from a sample of fertilizer, how grams of phosphorous were in the fe

In-s [12.5K]

1.34 grams of MgNH4PO4*6H2O
Molar mass= 245.1 grams per mole
Moles of MgNH4PO4*6H2O=
(1.34 grams)(1 mole/245.1 grams fertilizer)=0.0054671563 moles fertilizer
MgNH4PO4*6H2O has 1 mole of Phosphorous, so:
0.0054671563 moles fertilizer(1 mole Phosphorous/1 mole fertilizer)
0.0054671563 moles Phosphorous (30.97 grams/ 1 mole)
=0.1693178295 grams Phosphorous

4 0

3 years ago

Read 2 more answers

The table above shows the speed of sound through different materials. About how far can sound travel in air in 2.38 s if the air

kozerog [31]

(4) 615 m

Explanation:

From the table we see that the speed of sound in air at 20 °C is 343 m/s. Knowing this we devise the following reasoning:

if the sound travel through the air 343 meters in 1 second

then the sound travel through the air X meters in 2.38 seconds

X = (2.38 × 343) / 1 = 816.35 meters

Learn more about:

speed of sound

brainly.com/question/2279936

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8 0

3 years ago