Question

A 6.2 kg block is pushed across a horizontal surface

Answer 1

Answer:

6 m/s²

Explanation:

We are given;

• The mass of the block as 6.2 kg
• Horizontal force as 50.9 N
• Frictional force as 13.7 N

We are required to determine the acceleration of the block.

• According to second Newton's Law of motion; Resultant force is directly proportional to the rate of change in linear momentum.

Therefore;

F = Ma , where F is the resultant force, m is the mass and a is the acceleration.

In this case;

Resultant force, F = Horizontal force - friction force

                             = 50.9 N - 13.7 N

                             = 37.2 N

Thus;

37.2 N = 6.2 kg × a

Hence;

acceleration, a = 37.2 N ÷ 6.2 kg

                         = 6 m/s²

Therefore, the acceleration of the block is 6 m/s²