Answer:
<h3>14.97m/s</h3>
Explanation:
Given
Initial velocity of the car u = 8m/s
Distance travelled by the rider S = 40m
Acceleration a = 2m/s²
Required
rider's velocity after the acceleration v
Using the equation of motion
v² = u²+2as
v² = 8²+2(2)(40)
v² = 64+160
v² = 224
v = √224
v = 14.97m/s
Hence the rider's velocity after the acceleration is 14.97m/s
Point a because point a is the highest at potential energy converting into the highest kinetic energy.
Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).
<h3 /><h3>Line of code for force and acceleration</h3>
- In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies.
- Acceleration is a vector quantity (in that they have magnitude and direction).
- The direction of an object's acceleration is determined by the direction of the net force acting on it.
- Newton's Second Law states that the combined effect of two factors determines how much an item accelerates.
- The size of the net balance of all external forces acting on the object is, in accordance with the materials used to create it.
- It inversely proportional to its mass, whereas the magnitude of the net resultant force is directly proportional to the net force.
def force(mass, acceleration):
force_val = mass*acceleration
return force_val
10 is assigned to mass and 9.81 is assigned to acceleration
def force(10, 9.81)
So, Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).
Learn more about acceleration here:
brainly.com/question/460763
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Answer:
<h3>i think it is 7.10 </h3>
Explanation:
I dont have an explenation