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2 years ago

How many days would it take for a crepe myrtle tree to grow 1 cm in height if it grows 3.38 feet per year?

1 answer:

7 0

It's very easy, it's depending mainly on converting a mathematical unit:

When 1 Cm = 0.0328084 Ft
So, we assume that:
in 1 year → it grows 3.38 Ft

So X(years)→ 0.0328084

∴X(years) = 0.0328084 * 3.38 = 0.0097 year

We have to convert this unit form years to days by:

1 year = 365 days
So, 0.0097 = X (days)
∴X(days)= 365 * 0.0097 = 3.5 days

So it will take 3.5 days to grow up

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Select from the drop-down menu to correctly complete the statement.

Alenkasestr [34]

Answer:

C. have specific jobs

Explanation:

If an organism has specialized cells, then the cells performs specific jobs.

A group of cells that performs a specific job is called tissues.

In higher organisms, cells are specialized for specific purposes in them.
This is to ensure that cells are optimized to carry out certain functions.
Specialization of cells usually occurs by cellular differentiation when an organism begins to form.

7 0

3 years ago

You must make 1 L of 0.2 M acetic acid (CH3COOH). All you have available is concentrated glacial acetic acid (assay value, 98%;

Sergeu [11.5K]

Answer:

The correct answer is "11.44 ml".

Explanation:

Molarity,

= 0.2 M

Density,

= 1.05 g/ml

Volume,

= 1 L

As we know,

⇒ $Molarity=\frac{No. \ of \ moles }{Volume \ of \ solution}$

or,

⇒ $No. \ of \ moles=Molarity\times Volume$

On putting the values, we get

⇒ $=0.2\times 1$

⇒ $=0.2 \ moles$

Now,

⇒ $No. \ of \ moles=\frac{Mass \ taken}{Molecular \ mass}$

or,

⇒ $Mass \ taken=No. \ of \ moles\times Molecular \ mass$

⇒ $=0.2\times 60.05$

⇒ $=12.01 \ gram$

hence,

⇒ $Density= \frac{Mass }{Volume}$

or,

⇒ $Volume=\frac{Mass}{Density}$

⇒ $=\frac{12.01}{1.05}$

⇒ $=11.44 \ ml$

7 0

2 years ago

Help anyone can help me do this question,I will mark brainlest.

Anettt [7]

Answer:

12 grams

Explanation:

if you used the transformation equation you would end up with 12 grams

4 0

2 years ago

Write a balanced equation showing how this nucleus decays to form an α particle: thorium−230.

Ostrovityanka [42]

When an atomic nucleus emits an alpha particle it decay into an atom with atomic number 2 less and mass number 4 less. Thus Thorium 230 decay as follows.

230 90Th -------> 226 88Th + 4 2 He

thorium is in the atomic number 90 thus it during alpha decay it reduces to atomic number 88 while its 230 mass number reduces to 226

6 0

2 years ago

Predict whether each of the following bonds is ionic, polar, covalent, or nonpolar covalent:

Gekata [30.6K]

Explanation:

It is known that in order to determine a compound to be ionic, polar, covalent or non-polar covalent it is necessary to determine the electronegativity difference of the combining atoms.

So, when electronegativity difference is from 0.0 to 0.4 then bond formed between the two atoms is non-polar covalent in nature.

When electronegativity difference is greater than 0.4 and less than 1.8 then bond between the two atoms is a polar covalent bond.

When electronegativity difference is 1.8 or greater than the bond formed is ionic in nature.

Electronegativity difference of the given molecules is as follows.

Si-O = (1.90 - 3.44) = 1.54

K-Cl = (0.82 - 3.16) = 2.34

S-F = (2.58 - 3.98) = 1.4

P-Br = (2.19 - 2.96) = 0.77

Li-O = (0.98 - 3.44) = 2.46

N-P = (3.04 - 2.19) = 0.85

Therefore, given compounds are classified as follows.

Si-O, S-F, P-Br, and N-P all have a polar covalent bond. Whereas K-Cl and Li-O are ionic in nature.

7 0

3 years ago

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