Answer:
Q< K hence a precipitate will not form.
Explanation:
First convert the concentration to molL-1
For number of moles of K^+ = 0.05×20/1000 = 1×10^-3 moles
If we have 1×10^-3 moles in 20cm3
Then in 1000cm^3 we have 1×10^-3 moles×1000/20= 0.05 M
For ClO4^-= 0.50×80/1000= 0.04 moles
If we have 0.04 moles in 80cm3
Then in 1000cm^3 we have 0.04 moles×1000/80= 0.5 M
Q= [K^+] [ClO4^-]
Q= [0.05] [0.5]
Q= 0.025= 2.5×10-2
Q< K hence a precipitate will not form.
