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Trava [24]
3 years ago
8

The charge on a capacitor increases by 20 μC when the voltage across it increases from 84 V to 121 V. What is the capacitance o

f the capacitor?
Physics
1 answer:
Katena32 [7]3 years ago
3 0

Answer:

Capacitance of the capacitor = 0.547 F

Explanation:

We charge of capacitor,

            Q = CV

Let Q be the initial charge,we have voltage  = 84 V

             Q = C x 84 = 84 C

We have final charge = Q + 20.25  and voltage = 121 V

            Q + 20.25 = 121 C

Substituting Q value from previous equation

           84 C + 20.25 = 121 C

            37 C = 20.25

                 C = 0.547 F

Capacitance of the capacitor = 0.547 F

         

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Consider a cylindrical segment of a blood vessel 2.70 cm long and 3.10 mm in diameter. What additional outward force would such
Lyrx [107]

This question is incomplete, the complete question is;

- Calculate the difference in blood pressure between the feet and top of the head of a person who is 1.80m Tall

- Consider a cylindrical segment of a blood vessel 2.70 cm long and 3.10 mm in diameter. What additional outward force would such a vessel need to withstand in the person's feet compared to a similar vessel in her head

Answer:

- the difference in blood pressure is 18698.4 Pa

- the additional outward force F is 4.86 N

Explanation:

Given the data in the question;

we know that the expression for difference in blood pressure is;

ΔP = pgh

where p is density = 1060 kg/m³

g is acceleration due to gravity  = 9.8 m/s²

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now we substitute

ΔP = 1060 × 9.8 × 1.80

ΔP = 18698.4 Pa

therefore the difference in blood pressure is 18698.4 Pa

Also given that;

diameter of blood vessel d = 3.10 mm

radius r = 3.10 mm / 2 = 1.55 mm = 0.00155 m

length l = 2.70 cm = 0.027 m

Surface area of the cylindrical segment of a blood vessel is

A = 2πrl

we substitute

A = 2 × π × 0.00155 × 0.027

A = 2.6 × 10⁻⁴ m²

so

the required for will be;

F = PA

we substitute

F = 18698.4 Pa × 2.6 × 10⁻⁴ m²

F = 4.86 N

Therefore, the additional outward force F is 4.86 N

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bagirrra123 [75]

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The charges Q1=Q and Q2=4Q that are a distance d apart, repel each other with a force of 1.60 N. What would be the force between
gladu [14]

Answer:

50.4 N

Explanation:

Q1 = Q

Q2 = 4 Q

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F = \frac{KQ_{1}Q_{2}}{d^{2}}

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Now,

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Q4 = 7 Q

distance = d/3

F' = \frac{9KQ_{3}Q_{4}}{d^{2}}

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3 years ago
The phases of the moon are the changing appearances of the moon, as seen from Earth. Which phase happens immediately after a thi
Drupady [299]

The phases of the moon are the changing appearances of the moon, as seen from Earth. Which phase happens immediately after a third quarter moon are the following

Explanation:

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