Explanation:
The given data is as follows.
= 0, = 0, = 0
= 17.0 m, = 2.10 sec
As the force P is constant and the mass "m" of the tool is constant then it means that the acceleration "a" will also be constant.
Now,
=
17.0 = 2.205a
a =
Also, we know that
F =
m =
So, m =
= 1.66 kg
Since, the tool is subject to its weight W and is in free fall. Hence,
10.0 m =
g = 2.411
Hence, weight of tool in Newtonia is as follows.
W = mg
=
= 4.00 N
Hence, weight of the tool on Newtonia is 4.00 N.
And, weight of the tool on the Earth is as follows.
W =
= 23.62 N
Hence, weight of the tool on Earth is 23.62 N.
Answer:
Explanation:
Remark
This is a momentum question. Both cars are sitting still (v1 and v2 are both 0) to start with). When the spring is sprung), they both move but in opposite directions.
Let us say that v4 is minus.
Equation
0 = m3*v3 - m4* v4
Givens
m3 = 1750 kg
m4 = 1000 kg
v3 = 4 m/s
Solution
m3*4m/s - m4*x = 0
1750 * 4 - 1000*x = 0
1750 * 4 = 1000x
7000 = 1000 x
7000/1000 = x
x = 7 m/s
the answer A. since power is Joules/seconds and energy is rated in Joules
Answer:
a force is represented by a<u> vector </u>the choice of a <u>reference frame</u> is necessary
Explanation:
Answer:
D
Explanation:
the total speed and the total mass of the entire system remain the same weather one object is moving or stationary.
When two or more objects collide, the collision does not change the
total momentum of the two objects.
Whatever momentum is lost by one object in the collision is gained
by the other. The total momentum of the system is conserved.