Answer:
Sodium-vapour lights
Explanation:
Sodium-vapour lights are lights that are a type of gas discharge lamp that uses sodium in a high energy state to produce light,sodium discharge lamps are one of the brightest form of lighting used in motor parks and streets. There are basically two types of sodium-vapour lights, they include the low pressure sodium-vapour lights and the high pressure sodium-vapour lights.
Answer:
![0.3\ \text{m}^3/\text{kg}](https://tex.z-dn.net/?f=0.3%5C%20%5Ctext%7Bm%7D%5E3%2F%5Ctext%7Bkg%7D)
![36\ \text{kJ}](https://tex.z-dn.net/?f=36%5C%20%5Ctext%7BkJ%7D)
![18\ \text{kJ/kg}](https://tex.z-dn.net/?f=18%5C%20%5Ctext%7BkJ%2Fkg%7D)
Explanation:
V = Volume of air = ![0.6\ \text{m}^3](https://tex.z-dn.net/?f=0.6%5C%20%5Ctext%7Bm%7D%5E3)
P = Power = 10 W
t = Time = 1 hour
m = Mass of air = 2 kg
Specific volume is given by
![v=\dfrac{V}{m}\\\Rightarrow v=\dfrac{0.6}{2}\\\Rightarrow v=0.3\ \text{m}^3/\text{kg}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7BV%7D%7Bm%7D%5C%5C%5CRightarrow%20v%3D%5Cdfrac%7B0.6%7D%7B2%7D%5C%5C%5CRightarrow%20v%3D0.3%5C%20%5Ctext%7Bm%7D%5E3%2F%5Ctext%7Bkg%7D)
The specific volume at the final state is ![0.3\ \text{m}^3/\text{kg}](https://tex.z-dn.net/?f=0.3%5C%20%5Ctext%7Bm%7D%5E3%2F%5Ctext%7Bkg%7D)
Work done is given by
![W=Pt\\\Rightarrow W=10\times 60\times 60\\\Rightarrow W=36000\ \text{J}=36\ \text{kJ}](https://tex.z-dn.net/?f=W%3DPt%5C%5C%5CRightarrow%20W%3D10%5Ctimes%2060%5Ctimes%2060%5C%5C%5CRightarrow%20W%3D36000%5C%20%5Ctext%7BJ%7D%3D36%5C%20%5Ctext%7BkJ%7D)
The energy transfer by work, is ![36\ \text{kJ}](https://tex.z-dn.net/?f=36%5C%20%5Ctext%7BkJ%7D)
Change in specific internal energy is given by
![\Delta u=\dfrac{Q}{m}+\dfrac{W}{m}\\\Rightarrow \Delta u=0+\dfrac{36}{2}\\\Rightarrow \Delta u=18\ \text{kJ/kg}](https://tex.z-dn.net/?f=%5CDelta%20u%3D%5Cdfrac%7BQ%7D%7Bm%7D%2B%5Cdfrac%7BW%7D%7Bm%7D%5C%5C%5CRightarrow%20%5CDelta%20u%3D0%2B%5Cdfrac%7B36%7D%7B2%7D%5C%5C%5CRightarrow%20%5CDelta%20u%3D18%5C%20%5Ctext%7BkJ%2Fkg%7D)
The change in specific internal energy of the air is ![18\ \text{kJ/kg}](https://tex.z-dn.net/?f=18%5C%20%5Ctext%7BkJ%2Fkg%7D)
Answer:Well it depends on what the heavy load is but it is mostly easy to do it with a crowbar because it gives you leverage and it is stronger.
Explanation:
Your welcome I think.
Options:
1.Case
C2.It will be the same in all three cases.
3.Case A
4.Case B
Answer:C2. It will be the same in all three cases.
Explanation:In the above scenerio,
F, is the only net force that is acting on the System. Hence, the acceleration of the center of mass (a point in an object where a force can be applied to cause a linear acceleration without leading to an angular acceleration)is the same in each of the cases highlighted.The torque(the rotational equivalent of a linear force) depends on where the force acts.