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weqwewe [10]
2 years ago
12

what is the pressure exerted, what is the pressure exerted by 50kg girl as she places her weight on one shoe if the heels area i

s 0.002m²​
Physics
1 answer:
lana [24]2 years ago
6 0

Answer:

The pressure exerted by the girl is 245,000 N/m²

Explanation:

Given;

mass of the girl, m = 50 kg

area of the girl's shoe, A = 0.002 m²

The pressure exerted by the girl is calculated as follows;

P = \frac{F}{A} \\\\Where;\\F \ is \ the \ force \ exerted \ by \ girl's \ weight\\\\P = \frac{F}{A} = \frac{mg}{A} = \frac{50 \times 9.8}{0.002} = 245,000 \ N/m^2

Therefore, the pressure exerted by the girl is 245,000 N/m²

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The answer is: none of the above.

Explanation:

When light reflects from a surface, the frequency, wavelength, and speed do not change. They remain the same.
6 0
2 years ago
Since the aluminum bar is not an isolated system, the second law of thermodynamics cannot be applied to the bar alone. Rather, i
max2010maxim [7]

Answer:

ΔS total ≥ 0 (ΔS total = 0 if the process is carried out reversibly in the surroundings)

Explanation:

Assuming that the entropy change in the aluminium bar is due to heat exchange with the surroundings ( the lake) , then the entropy change of the aluminium bar is, according to the second law of thermodynamics, :

ΔS al ≥ ∫dQ/T

if the heat transfer is carried out reversibly

ΔS al =∫dQ/T  

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the total entropy change will be

ΔS total = ΔS al + ΔS surr

ΔS total ≥ ΔS al + (-ΔS al) =

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4 0
3 years ago
What name is given to the process that occurs when light passes from air to water?
-Dominant- [34]

Answer:

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5 0
3 years ago
The potential difference in a simple circuit is 2 v and the resistance is 2 ω . what current flows in the circuit? answer in uni
balandron [24]
Hey

Potential Difference given is : 2V

Resistance is : 2 ohms

By Ohm's Law, one can easily utilize the relation :

v = ir

Where, { v , i , r } are the potential difference, current and Resistance Respectively.


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i =  \frac{v}{r}  =  \frac{2}{2}  = 1a

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7 0
2 years ago
If an object is projected upward from ground level with an initial velocity of 144144 ft per​ sec, then its height in feet after
Liula [17]

Answer:

4.5 s, 324 ft

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The object is projected upward with an initial velocity of

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The equation that describes its height at time t is

s(t) = -16t^2 + 144 t (1)

where t, the time, is measured in seconds.

In order to find the time it takes for the object to reach the maximum height, we must find an expression for its velocity at time t, which can be found by calculating the derivative of the position, s(t):

v(t) = s'(t) = -32t +144 (2)

At the maximum heigth, the vertical velocity is zero:

v(t) = 0

Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:

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3 0
3 years ago
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