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gulaghasi [49]
3 years ago
5

Please this is important

Chemistry
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

Explanation:

2)

2C6H6 + 9O2 -> 12CO2 + 6H20

Weight of a CO2 Mol 12+ 16x2 = 44g

In 100g number of moles = 100/44= 2.2727 Moles

Number of C6H6 2moles burned when creating 12 moles of CO2

Therefore 2.2727/12 x 2 = 0.3787

3)  

3H2SO4 + 2Al(OH)3 -> Al2(SO4)3 + 6H2O

H2O weight of a 1mol is = 2+16 = 18g

2moles of Al(OH)3 cerates 6 moles of water.

3moles of sulfuric creates 6 moles of water.

5.5moles Al(OH)3 reacts with 5.5 moles of sulfuric

Therefore number of water moles = 5.5/3 x 6 = 11moles

Weight water = 11 x 18 = 198g

4)  

Cu + 2AgNO3 -> 2Ag + Cu(NO3)2

1mol of Cu produces 2moles of silver

Ag = 107.86 g/Mol

Cu = 63.54 g/Mol

In 26g Ag number of moles = (26/107.86)/2 x 63.54 = 7.658g

5)

3K2CrO4 + 2AlPO4 -> 2K3PO4 + Al2(CrO4)3

K2CrO4 = 39x2 + 52 + 16x4 = 194g/Mol

Al2(CrO4)3 = 54 + 354 = 408g/Mol

3moles of K2CrO4 creates 1mol of Al2(CrO4)3

Therefore weight of the Al2(CrO4)3 produced by 17.5g potassium chromate

(17.5/194)/3 moles of Al2(CrO4)3 produced  = 0.03moles

Al2(CrO4)3 produced = 0.03 x 408 = 12.26g

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<em><u>The initial entropy is obtained from the initial pressure and temperature with data from A-6 using interpolation:</u></em>

<em><u>s</u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em><em><u>.</u></em><em><u>26</u></em><em><u>5</u></em><em><u>2</u></em><em><u> </u></em><em><u>kJ</u></em><em><u>/</u></em><em><u>kgK</u></em>

<em><u>The final temperature is determined from the entropy and the final pressure with data from A-6 using interpolation:</u></em>

<em><u>T₂ = T₁+</u></em><em><u> </u></em><em><u>T₂ - </u></em><em><u>T₁</u></em><em><u>/</u></em><em><u> </u></em><em><u>8</u></em><em><u>₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8</u></em><em><u>₁</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>s</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>s</u></em><em><u>₁</u></em><em><u>)</u></em>

<em><u>= </u></em><em><u>(</u></em><em><u>400 +</u></em><em><u> </u></em><em><u>500 - 400</u></em><em><u>/</u></em><em><u>8.3271</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8.0347</u></em><em><u> </u></em><em><u>(8.2652 - 8</u></em><em><u>)</u></em><em><u>)</u></em>

<em><u>= 478.83°C</u></em>

<em><u>The final enthalpy is determined in the same way:</u></em>

<em><u>h₂= h₁</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>h₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>h₁</u></em><em><u>/</u></em><em><u>s</u></em><em><u>₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>s</u></em><em><u>₁</u></em><em><u> </u></em><em><u>( s - s₁)</u></em>

<em><u>= (</u></em><em><u> </u></em><em><u>3275.5</u></em><em><u>+</u></em><em><u> </u></em><em><u>3486.6 </u></em><em><u>-</u></em><em><u> </u></em><em><u>3275.5</u></em><em><u>/</u></em><em><u> </u></em><em><u>8.3271</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8.0347</u></em><em><u>)</u></em><em><u> </u></em><em><u>(8.265</u></em><em><u>)</u></em>

<em><u>=</u></em><em><u> </u></em><em><u>3441.91 </u></em><em><u>kJ</u></em><em><u>/</u></em><em><u>kg</u></em>

6 0
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