Answer:
100mL of 0.10M HNO2 and 0.10M NaNO2
Explanation:
because solution has the greatest buffering capacity when the concentration of the weak acid is = at the concentration of its conjugate base.
a) 3 molecule of carbon dioxide (CO2) - 3 carbon atoms
b) 6 molecule of 3 - PGA - 18 carbon atoms ( 3 cabon atoms in 1 3 PGA molecule)
c) 6 molecule og G3P - 18 carbon atom ( 3 carbon atoms in G3P molecule )
d) 5 molecules of G3P - 15 carbon atom
e) 3 molecule of R5P - 15 carbon atoms ( 5 carbon atom of R5P olecule )
f) 3 molecule of RuBP - 15 carbon atoms ( r carbon atom of RuBp molecule )
If one or more of the following occur: Gas formation, precipitate formation, color change, temperature change, or odor
Answer:
1) The correct step in the scientific method that Victor did is Construct a hypothesis.
2) Given mass and density, volume is calculated as mass divided by density.
Explanation:
1) Before doing the assay and make a graph with the results obtained, Victor should think what he wants to prove, so he should make a hypoythesis to test with the assay.
2) The formula of density is
density = mass/volume ⇒ density x volume = mass ⇒ volume = mass/density.
To know if the solutions are isotonic, hypertonic or hypotonic, we have to determine the osmotic pressure of each solution.
P = iMRT
where
i is the number of ions dissociated for strong electrolytes
M is the molarity
R is the universal gas constant
T is the absolute temperature
For 0.15 M CaCl₂, i = 3 (1 for Ca⁺ and 2 for Cl⁻).
P = (3)(0.15)RT= 0.45RT
For 0.15 NaCl, i = 2 (1 for Na⁺ and 1 for Cl⁻).
P = 2(0.15)RT = 0.3RT
Therefore, the P for CaCl₂ is GREATER than the P for NaCl. <em>Hence, the CaCl₂ solution is hypertonic.</em>