Ask question

Ask question

All categories

3 years ago

5

A block slides down a plane inclinded at an angle of 37° to the vertical with an acceleration of 6m/s each second. what is the c

oefficient of friction between the block and the plane?

1 answer:

Irina18 [472]3 years ago

6 0

Answer:

0.315

Explanation:

resolving weight into components and applying second law of motion we obtain the result

All has been explained in attachment

You might be interested in

A object of mass 33 is dropped from a height of 85 meters. Calculate the average power developed by the object in falling throug

DochEvi [55]

Power = Work done / Time taken.

Work done = mgh
Mass, m = 33kg ( Am presuming it is 33 kg).
h = 85 m.
Work done = 33 * 9.81* 85 = 27517.05 J.

Time taken.
Since object was dropped from height, it fell under gravity.
Using H = ut + (1/2) * gt^2. u = 0.
   H = 1/2 gt^2.
   t =   (2H/g) ^ (1/2)
   t = (2*85/9.81) ^ 0.5 = 4.1628 s.

Power = 27517.05 / 4.1628 = 6610.23 Watts.
   = 6610 W to 3 S. f.

3 0

3 years ago

To model this process, assume two charged spherical conductors are connected by a long conducting wire and a 1.20-mC charge is p

il63 [147K]

Answer:

Part a: The electric potential of each sphere is 1.35x10⁸V

Part b: The electric field at the surface of sphere 1 and 2 is 2.25x10⁹ N/C and 6.75x10⁹ N/C respectively

Explanation:

As the complete question is not given, the similar question is attached herewith. The values are used as indicated in the given question

Let r_1 = 6 cm=0.06 m

r2 = 2 cm = 0.02 m

Q = 1.2 mC

Let q1 and q2 are the charges on each sphere.

q1 + q2 = 1.2 mC -------(1)

In the equilibrium, V1 = V2

k*q1/r1 = k*q2/r2

q1/0.06 = q2/0.02

q1/q2 = 0.06/0.02

q1/q2 = 3 ---------(2)

On solving equation 1 and 2

we get

q1 = 0.9 mC

q2 = 0.3 mC

So

V1 = k*q1/r1 = (9*10^9*0.9*10^-3)/0.06 = 1.35*10^8 Volts

V2 = k*q2/r2 = 9*10^9*0.3*10^-3/0.02 = 1.35*10^8 Volts

So the electric potential of each sphere is 1.35x10⁸V

Part b

Now the electric potential is given as

E1 = k*q1/r1^2 = 9*10^9*0.9*10^-3/0.06^2 = 2.25*10^9 N/C

E2 = k*q2/r2 = 9*10^9*0.3*10^-3/0.02^2 = 6.75*10^9 N/C

So the electric field at the surface of sphere 1 and 2 is 2.25x10⁹ N/C and 6.75x10⁹ N/C respectively

7 0

3 years ago

Where does air pressure come from ______ tiny pieces of stuff

vesna_86 [32]

Molecules, The movemnet of molecules

5 0

3 years ago

The type of friction between the pavement and the tires on a moving vehicle is called.._____friction.

FinnZ [79.3K]

Answer:

A) Kinetic

Explanation:

Kinetic friction is friction caused by motion. Kinetic energy is energy in motion.

5 0

3 years ago

A delivery truck leaves a warehouse and travels 2.60 km north. The truck makes a left turn and travels 1.25 km west before makin

yulyashka [42]

Answer:

4.19 km and 107.35 degrees north of east

Explanation:

So in the end, the truck is (2.6 + 1.4 = 4km) north and 1.25 km west from the warehouse. We can use the Pythagorean formula to calculate the magnitude and direction α of the truck displacement from the warehouse:

$s = \sqrt{s_n^2 + s_w^2} = \sqrt{4^2 + 1.25^2} = \sqrt{16 + 1.5625} = \sqrt{17.5625} = 4.19$ km

$tan\alpha = \frac{s_n}{s_w} = \frac{4}{1.25} = 3.2$

$\alpha = tan^{-1}3.2 = 1.27 rad \approx 72.65 degrees$ north or west or (180 - 72.65) = 107.35 degrees north of east

3 0

3 years ago