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Igoryamba
4 years ago
5

A block slides down a plane inclinded at an angle of 37° to the vertical with an acceleration of 6m/s each second. what is the c

oefficient of friction between the block and the plane?​
Physics
1 answer:
Irina18 [472]4 years ago
6 0

Answer:

0.315

Explanation:

resolving weight into components and applying second law of motion we obtain the result

All has been explained in attachment

Download pdf
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Issac and Blaise decide to race. They both start at the same position at the same time. Issac runs at 2m/s but decides to take a
FromTheMoon [43]

Let the Blaise runs for time "t" to complete the race

so the total distance he moved is given by

d_1 = 1* t

Now Issac runs for time t = "t - 2*60"

because it took rest for 2 minutes

d_2 = 2*(t - 120)

now it is given that Blaise wins by 10 m distance

d_1 - d_2 = 10

1* t - 2*(t - 120) = 10

t - 2t + 240 = 10

t = 230 s

now the distance moved by Blaise is given by

d_1 = 1*230 = 230 m

6 0
3 years ago
A point charge gives rise to an electric field with magnitude 2 N/C at a distance of 4 m. If the distance is increased to 20 m,
worty [1.4K]

Answer:

0.08 N/C

Explanation:

Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,

E = Kq/r².............................. Equation 1

Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.

making q the subject of the equation,

q = Er²/k............................... Equation 2

Given: E = 2 N/C, r = 4 m,

Substitute into equation 2

q = 2(4)²/k

q = 32/k C.

When r is increased to 20 m,

E = k(32/k)/20²

E = 32/400

E = 0.08 N/C.

Hence the electric Field = 0.08 N/C

5 0
4 years ago
A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at
natka813 [3]
First you will want to sketch out both of the situations. It should be two sketches, one for the flagpole and one for the building.

To solve this, you will want to create a proportion.

Flagpole height/flagpole shadow=building height/building shadow

Therefore, it should look like this:
50/30= 300/x

Solve for x:
50x=9,000
X= 180 feet

YOUR ANSWER IS C.
7 0
3 years ago
An ice-skater is moving at a constant velocity across an icy pond, The skater throws a snowball directly ahead.
Murljashka [212]

Answer:

(D) It is equal to the original velocity of the skater.

Explanation:

The velocity of the center of mass of a system is

\vec{v}_{cm} = \frac{m1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}

The velocity of the center of mass is constant if there is no external force, because the total momentum of the whole system is conserved.

So, before the snowball is thrown, the velocity of the center of mass is equal to that of the skater. This velocity will always be equal to the velocity of the center of mass of the system.

6 0
3 years ago
Define total mechanical energy
zavuch27 [327]

Answer:

The total mechanical energy is the sum of kinetic and potential energies: E = K + U. The law of conservation of total mechanical energy states that the sum of the kinetic energy and potential energy is constant in time.

3 0
3 years ago
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