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Orlov [11]
3 years ago
14

14. Carbon-14 emits beta radiation and decays with a half-life (t) of 5730 years. Assume

Chemistry
1 answer:
Marizza181 [45]3 years ago
6 0

Answer: 375 g

Explanation:

Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives = ?

a_o = Initial amount of the reactant = 100 g

n = number of half lives = 4

Putting values in above equation, we get:

a=\frac{6000}{2^4}

a=375g

Therefore, the amount of carbon-14 remains at the end of four half-lives is 375 g

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7 0
3 years ago
If the atmospheric pressure is 0.975 atm what is the pressure of the enclosed gas
Nuetrik [128]
Missing in your question:
Picture (1)
when its an open- tube manometer and the h = 52 cm. 
when the pressure of the atmosphere is equal the pressure of the gas plus the pressure from the mercury column 52 Cm so, we can get the pressure of the gas from this formula:
P(atm) = P(gas) + height (Hg)
∴P(gas) = P(atm) - height (Hg)
              = 0.975 - (520/760) 
              = 0.29 atm
Note: I have divided 520 mm Hg by 760 to convert it to atm
Picture (2)
The pressure of the gas is the pressure experts by the column of mercury and when we have the Height (Hg)= 67mm 
So the pressure of the gas =P(atm) + Height (Hg)
                                             =  0.975 + (67/ 760) = 1.06 atm
Picture (3) 
As the tube is closed SO here the pressure of the gas is equal the height of the mercury column, and when we have the height (Hg) = 103 mm. so, we can get the P(gas) from this formula:
P(gas) = Height(Hg)
           = (103/760) = 0.136 atm

6 0
2 years ago
Can someone answer the bottom question (22-25)
Sindrei [870]
22) Oxygen with a -2 charge
23) Neon with a +2 charge
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3 years ago
If you wanted to find a sample of fermium,which has an atomic mass of 100,where would i look???
frutty [35]

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8 0
3 years ago
An unknown quantity of methane gas, CHA, is held in a 2.00-liter container at 77°C. The pressure inside the container is 3.00 am
kolbaska11 [484]

Answer:

0.21\text{ mol}

Explanation:

Here, we want to calculate the number of moles of methane in the container

From the ideal gas law:

\begin{gathered} PV\text{ = nRT} \\ n\text{ = }\frac{PV}{RT} \end{gathered}

where:

P is the pressure inside the container which is 3 atm

V is the volume of the container which is 2 L

R is the molar gas constant which is 0.0821 Latm/mol.k

T is the temperature in Kelvin (we convert the temperature in Celsius by adding 273 : 273 + 77 = 350 K)

n is the number of moles that we want to calculate

Substituting the values, we have it that:

n=\text{ }\frac{3\times2}{0.0821\text{ }\times350}\text{ = 0.21 mol}

6 0
10 months ago
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