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Orlov [11]
3 years ago
14

14. Carbon-14 emits beta radiation and decays with a half-life (t) of 5730 years. Assume

Chemistry
1 answer:
Marizza181 [45]3 years ago
6 0

Answer: 375 g

Explanation:

Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives = ?

a_o = Initial amount of the reactant = 100 g

n = number of half lives = 4

Putting values in above equation, we get:

a=\frac{6000}{2^4}

a=375g

Therefore, the amount of carbon-14 remains at the end of four half-lives is 375 g

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Why is boiling water a physical change
Harrizon [31]

Answer:

Boiling water is an example of a physical change and not a chemical change because the water vapor still has the same molecular structure as liquid water (H2O).

Explanation:

6 0
3 years ago
a 9.84 ounces ingot of unknown metal is heated from 73.2 degrees fahrenheit - 191.2 degrees fahrenheit this requires 3.912 calor
Gekata [30.6K]

The SI unit of specific heat is J per gram per degree Celsius. Thus it follows that specific heat could be calculated in this way:

Specific Heat = Energy / (mass x change in temperature)

Thus,

Specific Heat = 3.912 cal / (9.84 oz x (191.2 ˚F – 73.2 ˚F))

Specific Heat = 3.369 x 10^-3 cal/oz-˚F

6 0
4 years ago
A mixture of NaBrO 3 , NaBrO3, NaHCO 3 , NaHCO3, Na 2 CO 3 , Na2CO3, and NaBr NaBr was heated, producing H 2 O , H2O, CO 2 , CO2
nata0808 [166]

Answer:

Composition of initial mixture is:

9.02g of NaBrO₃

15.84g of  Na₂CO₃

17.06g of NaHCO₃

82.58g NaBr

Explanation:

For the reactions:

2NaBrO₃(s) ⟶ 2NaBr(s) + 3O₂(g)

2NaHCO₃(s) ⟶ Na₂O(s) + H₂O(g) + 2CO₂(g)

Na₂CO₃(s) ⟶ Na₂O(s)+CO₂(g)

All H₂O(g) comes from NaHCO₃. Thus, initial moles and mass of NaHCO₃ are:

1.83g H₂O ₓ (1 mol H₂O / 18.02g) ₓ (2 mol NaHCO₃ / 1 mol H₂O) = <em>0.203moles NaHCO₃</em> ₓ (84g / 1mol NaHCO₃) =

<em>17.06g of NaHCO₃</em>

CO₂ comes from NaHCO₃ and Na₂CO₃.

15.51g of CO₂ are:

15.51g CO₂ ₓ (1mol / 44.01g) =<em> 0.352moles of CO₂</em>

As 2 moles of NaHCO₃ produce 2 moles of CO₂, moles of CO₂ that comes from NaHCO₃ are 0.203moles NaHCO₃. Moles of CO₂ that comes from Na₂CO₃ are:

0.352mol CO₂ - 0.203mol CO₂ = <em>0.149mol CO₂</em>

<em />

These moles of CO₂ are produced from:

0.149mol CO₂ ₓ (1 mol Na₂CO₃ / 1 mol CO₂) ₓ (106g / 1mol Na₂CO₃) =

<em>15.84g of  </em>Na₂CO₃

And all O₂ comes from NaBrO₃. Initial mass of NaBrO₃ is:

2.87g O₂ ₓ (1 mol O₂ / 32g) ₓ (2 mol NaBrO₃ / 3 mol O₂) ₓ (150.9g / 1mol NaBrO₃) =

<em>9.02g of </em>NaBrO₃

If initial mass of the mixture was 124.5g, mass of NaBr was:

124.5g - 9.02g of NaBrO₃ - 15.84g of  Na₂CO₃ - 17.06g of NaHCO₃ =

<em>82.58g NaBr</em>

<em />

<em>Composition of initial mixture is:</em>

<em>9.02g of NaBrO₃</em>

<em>15.84g of  Na₂CO₃</em>

<em>17.06g of NaHCO₃</em>

<em>82.58g NaBr</em>

5 0
4 years ago
1.5L of water is boiled to steam at a temperature of 100 degrees Celsius and creates 3.5atm of pressure on the container. How ma
Lyrx [107]
I did for you hope you the best

5 0
3 years ago
If all of the above images represents the same material, which has the highest temperature?
aleksklad [387]

Answer:

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Explanation:

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