4 years ago

Question 3 of 5

Chemistry

1 answer:

jolli1 [7]4 years ago

6 0

Answer:

optionA

Explanation:

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If you have 8.5 moles of Al2(SO4)3 how many grams of the compound<br> do you have?

Zepler [3.9K]

Answer:

$RFM \: of \: aluminium \: sulphate = (2 \times 27) + (32 + (16 \times 4)) \times 3 \\ = 294 \\ 1 \: mole \: weighs \: 294 \: g \\ 8.5 \: moles \: weigh \: (8.5 \times 294) \: g \\ = 2499 \: g$

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Question 4 (4 points)

Fiesta28 [93]

I don’t know what is your problem

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3 years ago

Determine the value of the equilibrium constant for the following reaction, where the following amounts of each species are pres

dezoksy [38]

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3 years ago

The prefix 'mili-' means a thousandth. So a mili-liter is a thousandth of a liter. 1 mili-liter = 1/1000 liter How many liters i

Vesnalui [34]

it would be 0.623 hope this helps

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4 years ago