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ki77a [65]
3 years ago
11

lightning strikes in the distance and six seconds later Thunder is heard how far away was the lightning strike

Physics
1 answer:
marshall27 [118]3 years ago
8 0
The speed of sound really depends on the temperature and moisture in the air,
and the sound of the thunder doesn't necessarily travel straight from the lightning
to where you are.  So we can't say exactly. 

But if we use the nominal speed of 340 m/s, then 6 seconds means 2,040 meters,
or about 6,700 feet, or about 1.27 miles.
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Beryllium has a charge of +2, and bromine has a charge of –1. Which is the best name for the ionic bond that forms between them?
Feliz [49]

Answer:

Beryllium bromide

Explanation:

There exists 2 elements in the question

Beryllium Be with valence of +2, and it's a metal

Bromine Br with a valence of -1, and is a non - metal.

Both of them combine together forming an ionic bond:

Be + Br(2) -> BeBr(2)

In naming the compound, we would say that since the first is a metal, beryllium, and the second being a halogen, bromine. We name it by calling the first name together with the last name and changing the last name of the non metal from -ine to -ide.

So we have, Beryllium Bromide.

4 0
3 years ago
Two blocks of masses 1 = 700 and 2 = 1100 are connected by a cord of negligible mass and hung over a diskshaped pulley, as shown
ivanzaharov [21]

Answer:

b) 16 cm

Magnification, m = v/u

3 = v/u

⇒ v = 3u

Lens formula : 1/v – 1/u = 1/f

1/3u = 1/u = 1/12

-2/3u = 1/12

⇒ u = -8 cm

V = 3 × (-8) = -24

Distance between object and image = u – v = -8 – (-24) = -8 + 24 = 16 cm

Explanation:

3 0
3 years ago
An elevator provides 21 000 w of power during a 12 s ride. how much work does the elevator do?
nlexa [21]

Answer:

W=Px∆T= 21000x12=252.000J

8 0
3 years ago
HOW LONG WILL IT TAKE SHINTA TO REACH HIS BROTHERS LOCATION? PLS HELP
mylen [45]

Answer:

2 minutes or 120 seconds

Explanation:

The answer is 2 minutes or 120 seconds because 36 km is 36000 m and 36000 divided by 300 is 120, so the answer is 120 seconds, and converted to 2 minutes. Hope it helps!

3 0
3 years ago
A 1.10 μF capacitor is connected in series with a 1.92 μF capacitor. The 1.10 μF capacitor carries a charge of +10.1 μC on one p
miss Akunina [59]

Answer:

(a). The potential on the negative plate is 42.32 V.

(b). The equivalent capacitance of the two capacitors is 0.69 μF.

Explanation:

Given that,

Charge = 10.1 μC

Capacitor C₁ = 1.10 μF

Capacitor C₂ = 1.92 μF

Capacitor C₃ = 1.10 μF

Potential V₁ = 51.5 V

Let V₁ and V₂ be the potentials on the two plates of the capacitor.

(a). We need to calculate the potential on the negative plate of the 1.10 μF capacitor

Using formula of potential difference

V_{1}=\dfrac{Q}{C_{1}}

Put the value into the formula

V_{1}=\dfrac{10.1 \times10^{-6}}{1.10\times10^{-6}}

V_{1}=9.18\ V

The potential on the second plate

V_{2}=V-V_{1}

V_{2}=51.5 -9.18

V_{2}=42.32\ v

(b). We need to calculate the equivalent capacitance of the two capacitors

Using formula of equivalent capacitance

C=\dfrac{C_{1}\timesC_{2}}{C_{1}+C_{2}}

Put the value into the formula

C=\dfrac{1.10\times10^{-6}\times1.92\times10^{-6}}{(1.10+1.92)\times10^{-6}}

C=6.99\times10^{-7}\ F

C=0.69\ \mu F

Hence, (a). The potential on the negative plate is 42.32 V.

(b). The equivalent capacitance of the two capacitors is 0.69 μF.

7 0
3 years ago
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