Answer:
Beryllium bromide
Explanation:
There exists 2 elements in the question
Beryllium Be with valence of +2, and it's a metal
Bromine Br with a valence of -1, and is a non - metal.
Both of them combine together forming an ionic bond:
Be + Br(2) -> BeBr(2)
In naming the compound, we would say that since the first is a metal, beryllium, and the second being a halogen, bromine. We name it by calling the first name together with the last name and changing the last name of the non metal from -ine to -ide.
So we have, Beryllium Bromide.
Answer:
b) 16 cm
Magnification, m = v/u
3 = v/u
⇒ v = 3u
Lens formula : 1/v – 1/u = 1/f
1/3u = 1/u = 1/12
-2/3u = 1/12
⇒ u = -8 cm
V = 3 × (-8) = -24
Distance between object and image = u – v = -8 – (-24) = -8 + 24 = 16 cm
Explanation:
Answer:
W=Px∆T= 21000x12=252.000J
Answer:
2 minutes or 120 seconds
Explanation:
The answer is 2 minutes or 120 seconds because 36 km is 36000 m and 36000 divided by 300 is 120, so the answer is 120 seconds, and converted to 2 minutes. Hope it helps!
Answer:
(a). The potential on the negative plate is 42.32 V.
(b). The equivalent capacitance of the two capacitors is 0.69 μF.
Explanation:
Given that,
Charge = 10.1 μC
Capacitor C₁ = 1.10 μF
Capacitor C₂ = 1.92 μF
Capacitor C₃ = 1.10 μF
Potential V₁ = 51.5 V
Let V₁ and V₂ be the potentials on the two plates of the capacitor.
(a). We need to calculate the potential on the negative plate of the 1.10 μF capacitor
Using formula of potential difference

Put the value into the formula


The potential on the second plate



(b). We need to calculate the equivalent capacitance of the two capacitors
Using formula of equivalent capacitance

Put the value into the formula



Hence, (a). The potential on the negative plate is 42.32 V.
(b). The equivalent capacitance of the two capacitors is 0.69 μF.