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3 years ago

Como se distribuyen los elementos en la tabla periodica

Chemistry

1 answer:

Kitty [74]3 years ago

7 0

Answer:

La versión moderna de la tabla periódica de los elementos contiene los elementos ordenados según su número atómico creciente, y distribuidos en siete (7) filas horizontales llamadas períodos y dieciocho (18) columnas verticales llamadas grupos, de tal forma que los elementos en el mismo grupo tienen propiedades similares.

Explanation:

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alexgriva [62]

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Explanation:

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2 years ago

What is a combination of two or more substances that are all solids

Sophie [7]

Answer:

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7 0

3 years ago

Which group (give the number) is characterized by 5 valence electrons in the configuration<br> s²p3?

Ivahew [28]

<h3>Answer:</h3>

Group 5A

<h3>Explanation:</h3>

Elements in the periodic table are arranged into columns known as groups and rows known as periods.
Elements in the same group share similar chemical properties.
For example, elements in group 5A have five valence electrons with the most high energy level with a configuration of s²p³.
Elements in group 5A include nitrogen and phosphorus among others.

5 0

3 years ago

1826.5g of methanol (CH3OH), molar mass = 32.0 g/mol is added to 735 g of water, what is the molality of the methane 0.0348 m 1.

Snowcat [4.5K]

Answer:

Molality = 1.13 m

Explanation:

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

Mass of $CH_3OH$ = 26.5 g

Molar mass of $CH_3OH$ = 32.04 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{26.5\ g}{32.04\ g/mol}$

$Moles\ of\ CH_3OH= 0.8271\ moles$

Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )

So, molality is:

$m=\frac {0.8271\ moles}{0.735\ kg}$

<u>Molality = 1.13 m</u>

4 0

3 years ago

How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 4.46 atm and 45°C in the reaction shown below?

natka813 [3]

Answer:

8.1433 g of XeF₆ are required.

Explanation:

Balanced chemical equation;

XeF₆ (s) + 3H₂ (g) → Xe (g) + 6HF (g)

Given data:

Volume of hydrogen = 0.579 L

Pressure = 4.46 atm

Temperature = 45 °C (45+273= 318 k)

Solution:

First of all we will calculate the moles of hydrogen

PV = nRT

n = PV/ RT

n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K

n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹

n = 0.0995 mol

Mass of hydrogen:

Mass = moles × molar mass

Mass = 0.0995 mol × 2.016 g/mol

Mass = 0.2006 g

Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.

H₂ : XeF₆

3 : 1

0.0995 : 1/3× 0.0995 = 0.0332 mol

Now we will calculate the mass of XeF₆.

Mass = moles × molar mass

Mass = 0.0332 mol × 245.28 g/mol

Mass = 8.1433 g

4 0

3 years ago