Question

Given a solution with a pOH of 13.6, what is the [OH-] of the solution?

Answer 1

10^-13.6 = 2.51x10^-14

Answer 2

Answer:

2.51 x 10-14 M

Explanation:

The definition of pOH is:

pOH = -log[OH-]

then, clearing of the equation [OH-] we have:

-pOH = log[OH-]

By properties of logarithms:

$[OH-] = 10^{-pOH}$

Replacing the values:

$[OH-] = 10^{-13.6}$

And if you use a calculator, you will see that $10^{-13.6}=2.51x10^{-14}$