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iren2701 [21]
3 years ago
9

Give what you now know about the transportation industry, describe in 50 words or less some key issues which are likely to limit

a person's successful pursuit of a career in the industry
Engineering
1 answer:
brilliants [131]3 years ago
6 0
Moreover, these debates often focus on some topics at the expense of other equally important issues. For example, there is a legitimate concern ...
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Which of the following qualities of large man-made structures is unique to dams? They span water bodies They generate electricit
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They generate electricity.

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Suppose you want to buy a new car. The car will be used mainly for going to work, shopping, running errands, and visiting friend
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1. So you can complete the things you NEED to do faster. (I.e work, groceries)

2. So it’s easier for you to do leisure activities. (I.e visiting friends, shopping)
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3 years ago
One problem with organic equations is that we tend to focus on what is happening to onemolecule at a time, we forget that there
stellarik [79]

Answer:

1 2 200 000 000 000 000 000 000 (20 zeros) molecules

Explanation:

Molar mass of 1-butanol = 74.121 g/mol

number of moles = mass given / molar mass

where mass given = 1.5 g

number of mole = 1.5 g / (74.121g/mol ) = 0.0202 moles

number of moles = number of molecules / Avogadro's constant

where Avogadro's = 6.022 × 10²³ mol⁻¹

number of moles = 6.022 × 10²³ × 0.0202 moles = 1 2 200 000 000 000 000 000 000 (20 zeros) molecules

3 0
3 years ago
A circular column is fixed at the base and not supported at the top. If the column needs to be 15ft and hold 10kips, what is the
muminat

Answer:

The required size of column is length = 15 ft and diameter = 4.04 inches

Explanation:

Given;

Length of the column, L = 15 ft

Applied load, P = 10 kips = 10 × 10³ Psi

End condition as fixed at the base and free at the top

thus,

Effective length of the column, \L_e = 2L = 30 ft = 360 inches

now, for aluminium

Elastic modulus, E = 1.0 × 10⁷ Psi

Now, from the Euler's critical load, we have

P =\frac{\pi^2EI}{L_e^2}

where, I is the moment of inertia

on substituting the respective values, we get

10\times10^3 =\frac{\pi^2\times1.0\times10^7\times I}{360^2}

or

I = 13.13 in⁴

also for circular cross-section

I = \frac{\pi}{64}\times d^4

thus,

13.13 = \frac{\pi}{64}\times d^4

or

d = 4.04 inches

The required size of column is length = 15 ft and diameter = 4.04 inches

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3 years ago
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Yes that is right no matter what you are talking about I’m not sure tho
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