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2 years ago

9

Give what you now know about the transportation industry, describe in 50 words or less some key issues which are likely to limit

a person's successful pursuit of a career in the industry

1 answer:

brilliants [131]2 years ago

6 0

Moreover, these debates often focus on some topics at the expense of other equally important issues. For example, there is a legitimate concern ...

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The first step to merging is entering the ramp and _____.

Yuri [45]

Answer:

D.telling your passengers where you are going

7 0

3 years ago

A centrifugal pump is required to pump water to an open water link situated 4 km away from the location of the pump through a pi

11111nata11111 [884]

Answer:

P= 5.5 bar

Explanation:

Given that

L= 4000 m

d= 0.2 m

Friction factor(F) = 0.01

speed V= 2 m/s

Head = 5 m

Head loss due to friction

$h_f=\dfrac{FLV^2}{2gd}$

$h_f=\dfrac{0.01\times 4000\times 2^2}{2\times 9.81\times 0.2}$

$h_f=40.77m$

So the total head(H) = 5 + 40.77 + 10.3 =56.07

Where 10.3 m is the atmospheric head.

We know that

P=ρ g H

So total Pressure

P= 1000 x 9.81 x 56.07 Pa

$P=5.5\times 10^5\ Pa$

P= 5.5 bar

5 0

3 years ago

R-744 refrigerant is bad why

mars1129 [50]

Answer:

Explanation:

R-744 is seen as the 'perfect' natural refrigerant as it is climate neutral and there is not a flammability or toxicity risk. It is rated as an A1 from ASHRAE. While it is non-toxic there is still risk if a leak occurs in an enclosed area as R-744 will displace the oxygen in the room and could cause asphyxiation

6 0

3 years ago

Hey, I have a question, I was thinking that if you have engineering skills or drawing skill you could help me to start a project

gayaneshka [121]

Answer

Dont have one;(

Explanation:

7 0

2 years ago

Determine the reactor volume (assume a CSTR activated sludge aerobic reactor at steady state) required to treat 5 MGD of domesti

12345 [234]

Answer:

1.0MG

Explanation:

to solve this problem we use this formula

S₀-S/t = ksx --- (1)

the values have been given as

concentration = S₀ = 250mg

effluent concentration = S= 10mg

value of K = 0.04L/day

x = 3000 mg

when we put these values into this equation,

250-10/t = 0.04x10x3000

240/t = 1200

we cross multiply from this stage

240 = 1200t

t = 240/1200

t = 0.2

remember the question says that 5MGD is required to be treated

so the volume would be

v = 0.2x5

= 1.0 MG

4 0

2 years ago