Question

Determine the electrical and gravitational forces that two protons in the nucleus of a helium atom exert on each other when separated by 3.0×10−15m. Express your answer to two significant figures and include the appropriate units (G = 6.67 × 10-11 N ∙ m2/kg2, Mproton = 1.6726231 × 10-27 kg, Qproton, 1.6021 × 10-19 C K = 9 × 109 N ∙ m2/C2)

Answer 1

Answer:

Fe = 25.67 N

Fg = 2.0734 x 10^-35 N

Explanation:

r = 3 x 10^-15 m

G = 6.67 x 10^-11 Nm^2/kg^2

Mp = 1.6726231 x 10^-27 kg

Qp = 1.6021 x 10^-19 C

K = 9 x 10^9 Nm^2/C^2

The formula for the electrical force between the two protons is given by

$F = K \frac{Q_{p}\times Q_{p}}{r^{2}}$

$F = \frac{9\times 10^{9}\times 1.6021\times 10^{-19}\times 1.6021\times 10^{-19}}{3\times 10^{-15}\times 3\times 10^{-15}}$

Fe = 25.67 N

The formula for the gravitational force between the two protons is given by

$F = G \frac{M_{p}\times M_{p}}{r^{2}}$

$F = \frac{6.67\times 10^{-11}\times 1.6726231\times 10^{-27}\times 1.6726231\times 10^{-27}}{3\times 10^{-15}\times 3\times 10^{-15}}$

Fg = 2.0734 x 10^-35 N