Answer:
184.113 g/mol
Explanation: The atomic mass of Mg is 24.3 amu. The atomic mass of bromine is 79.9. Therefore, the formula weight of MgBr2 equals 24.3 amu + (2 × 79.9 amu), or 184.1 amu. Because a substance's molar mass has the same numerical value as its formula weight, the molar mass of MgBr2 equals 184.1 g/mol.
Alkali metals have the lowest electronegativities, while halogens have the highest.
Answer : The ratio of 
to 
is, 
Solution : Given,
= 0.21 atm
The given equilibrium reaction is,
The expression of 
will be,
Now put all the given values in this expression, we get:
Therefore, the ratio of to is,
Answer:
I need the columns to do the question
Explanation:
