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mario62 [17]
3 years ago
9

Answer these question with full step​

Physics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answers

AnswersGiven, the radius of the wheel is 1m. so,its circumference is 2π m

AnswersGiven, the radius of the wheel is 1m. so,its circumference is 2π mwhen it rotates half, the initial point of contact is vertically above the final point of contact.thus,the three points form a right triangle.

AnswersGiven, the radius of the wheel is 1m. so,its circumference is 2π mwhen it rotates half, the initial point of contact is vertically above the final point of contact.thus,the three points form a right triangle.by pythagoras theorem, we solve it to get the magnitude of displacement,which is the hypotenuse.

AnswersGiven, the radius of the wheel is 1m. so,its circumference is 2π mwhen it rotates half, the initial point of contact is vertically above the final point of contact.thus,the three points form a right triangle.by pythagoras theorem, we solve it to get the magnitude of displacement,which is the hypotenuse.thus, d=√4+π²

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A 150-W lamp is placed into a 120-V ac outlet. What is the peak current?
devlian [24]

Answer:

Explanation:

Formula

W = I * E

Givens

W = 150

E = 120

I = ?

Solution

150 = I * 120   Divide by 120

150/120 = I

5/4  = I

I = 1.25

Note: This is an edited note. You have to assume that 120 is the RMS voltage in order to go any further. That means that the peak voltage is √2 times the size of 120. The current has the same note applied to it. If the voltage is its rms value, then the current must (assuming the properties of the bulb do not change)

On the other hand, if the voltage is the peak value at 120 then 1.25 will be correct.

However I would go with the other answerer's post and multiply both values by  √2

3 0
3 years ago
Read 2 more answers
Sharon the ant (Aaron’s sister) sits at the edge of a turntable of radius R that is spinning with period T. As she makes one-hal
Dmitry_Shevchenko [17]

Answer:

a = \dfrac{4\pi^2R}{T^2}

Explanation:

The acceleration of a circular motion is given by

a = \omega^2 R

where \omega is the angular velocity and R is the radius.

Angular velocity is related to the period, T, by

\omega=\dfrac{2\pi}{T}

Substitute into the previous formula.

a = (\dfrac{2\pi}{T})^2 R

a = \dfrac{4\pi^2R}{T^2}

This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.

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On the weather map, what does the symbol shown below represent?
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Answer:

wind speed i think where i live?

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Compared to Earth's moon, the moons of Mars are
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I think is b I think
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An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
ohaa [14]

Answer:

The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.

F = N e E     where E is the value of the field and N e the charge Q

M g = N e E      and M g is the weight of the drop

N = M g / (e E)

N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13

.00011 kg is a very large drop

Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs

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7 0
2 years ago
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