Complete the reactions to show how butanoic acid may be converted to phenyl propyl ketone.
1 answer:
Phenyl Propyl Ketone is prepared from Butanoic acid as follow,
First Butanoic acid is treated with thionyl chloride so to change the -OH group into good leaving group (i.e. -Cl) and Butyryl chloride is generated.
Secondly, Chlorination of Benzene is done to synthesize chlorobenzene which on treatment with Mg metal in ether is converted into Phenyl Magnesium Chloride, which acts as a nucleophile and attacks the carbonyl carbon of Butyryl Chloride and upon hydrolysis gives Phenyl Propyl Ketone as shown below,
First Butanoic acid is treated with thionyl chloride so to change the -OH group into good leaving group (i.e. -Cl) and Butyryl chloride is generated.
Secondly, Chlorination of Benzene is done to synthesize chlorobenzene which on treatment with Mg metal in ether is converted into Phenyl Magnesium Chloride, which acts as a nucleophile and attacks the carbonyl carbon of Butyryl Chloride and upon hydrolysis gives Phenyl Propyl Ketone as shown below,
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Answer:
Bond energy of carbon-fluorine bond is 485 kJ/mol
Explanation:
Enthalpy change for a reaction, is given as:
Where and
represents average bond energy in breaking "i" th bond and forming "j" th bond respectively.
and
are number of moles of bond break and form respectively.
In this reaction, one mol of C=C, four moles of C-H and one mol of F-F bonds are broken. One mol of C-C bond, four moles of C-H bonds and two moles of C-F bonds are formed
So,
or,
or,
So bond energy of carbon-fluorine bond is 485 kJ/mol