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GarryVolchara [31]
3 years ago
13

If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be

Chemistry
2 answers:
Goryan [66]3 years ago
8 0
CH4 + 2O2 → 2CO + 2H2O
geniusboy [140]3 years ago
4 0

The answer is C.) CO

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Nkjnkjnknjknkjnnkjnknjkkjnjknj
ollegr [7]

Answer:

what

Explanation:

3 0
2 years ago
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Sucrose, a major product of photosynthesis in green leaves, is synthesized by a battery of enzymes. The substrates for sucrose s
Gwar [14]

Answer:

Sucrose is a disaccharide composed of alpha D gluose and beta D fructose linked together by beta 2,alpha1 glycosidic linkage.

Explanation:

The specificity of glycosidic linkage very much essential to choose the substrate for the synthesis of specific disaccharide.

 For example sucrose contain beta 2,alpha1 glycosidic linkage that means the hydroxyl group of anomeric carbon of one monosaccharide(fructose) should remain in beta conformation and the hydroxyl group of other monosaccharide(glucose) should remain in alpha conformation.

   

5 0
3 years ago
Determine the molarity of a solution formed by dissolving 97.7 g libr in enough water to yield 750.0 ml of solution.
rewona [7]

Answer:

1.5 M.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

<em>M = (no. of moles of LiBr)/(Volume of the solution (L).</em>

<em></em>

∵ no. of moles of LiBr = (mass/molar mass) of LiBr = (97.7 g)/(86.845 g/mol) = 1.125 mol.

Volume of the solution = 750.0 mL = 0.75 L.

∴ M = (no. of moles of luminol)/(Volume of the solution (L) = (1.125 mol)/(0.75 L) = 1.5 M.

3 0
3 years ago
Read 2 more answers
How many moles of HCl are present in 4.7 L of a 4.23 M HCl solution?
REY [17]

Hey There!

Volume = 4.7 L

Molarity = 4.23 M

Therefore:

n = M *V

n = 4.23 * 4.7

n = 19.881 moles of HCl

hope this helps!

6 0
3 years ago
An electron in a hydrogen atom moves from level 3 to level 1. In a second hydrogen atom, an electron drops from level 2 to level
topjm [15]
I think the answer that you are looking for is B but im not a 100% sure

4 0
3 years ago
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