The kinetic energy of the mass at the instant it passes back through its equilibrium position is about 1.20 J

<h3>Further explanation</h3>
Let's recall Elastic Potential Energy formula as follows:

where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>
Let us now tackle the problem!

<u>Given:</u>
mass of object = m = 1.25 kg
initial extension = x = 0.0275 m
final extension = x' = 0.0735 - 0.0275 = 0.0460 m
<u>Asked:</u>
kinetic energy = Ek = ?
<u>Solution:</u>
<em>Firstly , we will calculate the spring constant by using </em><em>Hooke's Law</em><em> as follows:</em>






<em>Next , we will use </em><em>Conservation of Energy</em><em> formula to solve this problem:</em>







<h3>Learn more</h3>

<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity
Answer:At the top of the page is a transvers wave
C= crest
B= wavelingth
D= trough
A= amplatud
The next wave is a longitudinal wave
The particles vibrate against each other in a soild state........i think
f = frequency of the sound wave = 680 hertz
λ = wavelength of the sound wave = 0.5 meters
v = speed of sound wave
we know that , speed of sound wave is given as
speed of sound wave = frequency of sound wave x wavelength of sound wave
v = f λ
inserting the above values in the formula above
v = (680 hertz) (0.5 meters)
v = 340 meter/second
hence the speed of sound wave comes out to be 340 meter/second
The answer is 40 because you just have to do 200 divided by 5