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allsm [11]
2 years ago
10

Help please! based on the following table, which object has the lowest density? A. object A B. object B C. object C D. object D

Physics
2 answers:
seraphim [82]2 years ago
6 0
The answer to this question lies in the definition of density. One material will just float over another if its density is smaller. If one material is denser than the other, it will sink. Density can be defined as the mass per unit volume of a substance at a given pressure and temperature. Thus, for a material to float in water, it does not depend on the weight, or rather on the mass, but on the distribution of the mass by the volume occupied, that is, of the density. The more distributed the mass, that is, the larger its volume, the less dense the object and it will float.


Object C has the lowest density<span>
65 N or 6.5 Kg ------------ 6 N or 6 Kg

This effective mass under water will be its actual mass minus the mass of the fluid displaced. 

The buoyant force on a submerged object is equal to the weight of the fluid displaced.
Weight of object - buoyant force on object (the mass of the fluid displaced)

6Kg - 6.5Kg= - 0.5Kg

</span>Answer: C. object C
swat322 years ago
6 0

Answer:

C

Explanation:

As we know density is the ratio of mass to volume. As per the given data in table, Buoyant force is the repulsive force which is applied by the water or liquid in upward direction when an object is placed or merged in the liquid. An object will sink only when the buoyant force will be less than than the force applied from upward direction on that object, hence it will have greater density.

Of all the options available, only option C is the object which has the lowest density.

In this case the buoyant force is greater than the weight of the object hence the body will not sink, rather it will float on surface hence it has the lowest density of all.

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\texttt{ }

<h3>Further explanation</h3>

Let's recall Elastic Potential Energy formula as follows:

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\texttt{ }

<u>Given:</u>

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<u>Asked:</u>

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\texttt{ }

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Ek = \frac{1}{2}k (x')^2 + mgh - \frac{1}{2}k x^2

Ek = \frac{1}{2}k ( (x')^2 - x^2 ) + mgh

Ek = \frac{1}{2}(445 \frac{5}{11}) ( 0.0460^2 - 0.0275^2 ) + 1.25(9.8)(0.0735)

\boxed {Ek \approx 1.20 \texttt{ J}}

\texttt{ }

<h3>Learn more</h3>
  • Kinetic Energy : brainly.com/question/692781
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  • The Speed of Car : brainly.com/question/568302
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\texttt{ }

<h3>Answer details</h3>

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