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GenaCL600 [577]
3 years ago
14

A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO3. Determine the equilibrium pressure of NO2 if Kp for the reac

tion at this temperature is 0.0118. NO(g) SO3(g) NO2(g) SO2(g)
Chemistry
1 answer:
dlinn [17]3 years ago
4 0

Explanation:

Reaction equation for this reaction is as follows.

     NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)

It is given that K_{p} = 0.0118.

According to the ICE table,

              NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)

Initial:           0.86      0.86               0            0

Change:          -x          -x                 +x           +x

Equilibrium:  0.86 - x   0.86 - x         x           x

Hence, value of K_{p} will be calculated as follows.

           K_{p} = \frac{P_{NO_{2}} \times P_{SO_{3}}}{P_{NO} \times P_{SO_{3}}}

         0.0118 = \frac{x \times x}{(0.86 - x)^{2}}

             x = 0.084 atm

Thus, we can conclude that P_{NO_{2}} is 0.084 atm.

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