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amid [387]
3 years ago
7

A perfectly still 0.01 kg marble is hit with a force of 50 N by a pencil. According to Newton's third law, which describes the f

orce the marble exerts on the pencil? A. The marble exerts a force of 0.05 N on the pencil. B. The marble exerts a force of 0.5 N on the pencil. C. The marble exerts a force of 5 N on the pencil. D. The marble exerts a force of 50 N on the pencil.
Physics
1 answer:
WARRIOR [948]3 years ago
5 0

During the time that the pencil is exerting 50N of force on the marble, the marble is exerting 50N of force in exactly the opposite direction on the pencil. <em>(D)  </em>The mass of the marble doesn't matter, and it doesn't even matter whether the marble is moving or perfectly still.

As soon as the pencil stops exerting any force on the marble, the marble immediately stops exerting any force on the pencil.

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Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = \frac{mv}{qB}

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

8 0
3 years ago
An object falling under the influence of gravity and no other force is said to be
miv72 [106K]

Answer:

true

Explanation:

free fall is said to be the downward movement of an object under the force of gravity only

7 0
3 years ago
A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re
forsale [732]

Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

(1) we solve for the  initial potential energy stored

Thus,

V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

By using the energy conversion, we have the following

ΔV = mgh

=(0.1/9.8) * 9.8 * 1.5 = 0.15J

The internal energy = 0.2 -0.15

=0.05J

8 0
2 years ago
A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?
Yanka [14]

Answer:

\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 380.2 \times  {11}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 190.1 \times 121

\sf \implies KE = 190.1 \times 121

\sf \implies KE = 23002.1 \: J

\therefore

Kinetic energy of the polar bear (KE) = 23002.1 J

5 0
3 years ago
An ideal gas is at a pressure 1.00 Ã 105 n/m2 and occupies a volume 2.00 m3. if the gas is compressed to a volume 1.00 m3 while
blsea [12.9K]
The behavior of an ideal gas at constant temperature obeys Boyle's Law of
p*V = constant
where
p = pressure
V = volume.

Given:
State 1:  
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  V₁ = 2 m³
State 2:
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Therefore the pressure at state 2 is given by
p₂V₂ = p₁V₁
or
p₂ = (V₁/V₂) p₁
    = 2 x 10⁵ Pa

Answer: 2 x 10⁵ N/m² or 2 atm.
4 0
3 years ago
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