Answer: Velocity = v = 35 m/s
Explanation:
Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.
Mathematically,
v = 35 m/s
Answer:
F = 102 N
Explanation:
ASSUMING the track is horizontal to avoid gravity potential energy considerations.
The work of the applied force must overcome friction work and increase the kinetic energy of the runner
F(d) = Ff(d) + ½m(v² - u²)
F = Ff + m(v² - u²) / 2d
F = 30.0 + 60.0(8.00² - 2.00²) / (2(25.0))
F = 102 N
Show the graph. I need to see the graph first in order to get the awnser
Let l = Q/L = linear charge density. The semi-circle has a length L which is half the circumference of the circle. So w can relate the radius of the circle to L by
<span>C = 2L = 2*pi*R ---> R = L/pi </span>
<span>Now define the center of the semi-circle as the origin of coordinates and define a as the angle between R and the x-axis. </span>
<span>we can define a small charge dq as </span>
<span>dq = l*ds = l*R*da </span>
<span>So the electric field can be written as: </span>
<span>dE =kdq*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>dE = k*I*R*da*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>E = k*I*(sin(a)/R I_hat - cos(a)/R^2 j_hat) </span>
<span>E = pi*k*Q/L(sin(a)/L I_hat - cos(a)/L j_hat)</span>
